Python - 字典打印与他的值一样多的键

Question

I want to print out all the letters in my dictionary (seen at the last line of my code) the problem is that the output is aqlmui now. But as you guys can see the l in my dictionary is having a value of 2 so I want to print that out 2 times. so the output of my program should be: aqllmui.

Help would be appreciated a lot! :)

def display_hand(hand):

    row = ''
    for letter in hand:
        row += letter

       #I think i need to put an if statement here but I just don't know how to do it

    print row


display_hand({'a':1, 'q':1, 'l':2, 'm':1, 'u':1, 'i':1})

Answer 1

You can also try print "".join(k*v for (k,v) in s.iteritems()) .

Here k*v for (k,v) in s.iteritems() returns a list of key*value like ["a","i","m","ll","q","u"] and "".join(list) will join that list to make a string.

Answer 2

做就是了：

row += letter * hand[letter]

Answer 3

You can use string/int multiplication to perform multiple concatenations

for letter in hand:
    row += letter * hand[letter]

Or a little more clearly and efficiently:

for letter, count in hand.iteritems():  # Use hand.items() in Python 3
    row += letter * count