[英]How to sort a list of objects based on different object values in python?
I have a class with several different values. 我有一个有几个不同价值观的课程。 I would like to be able to sort a list of these object by the different values, but I am not sure how to do so.
我希望能够通过不同的值对这些对象的列表进行排序,但我不知道该怎么做。 I would like to be able to sort them for any of the values and for both directions (least to greatest and vice versa).
我希望能够为任何值和两个方向(最少到最大,反之亦然)对它们进行排序。
For example below is a sample class, along with a list of sample objects: 例如,下面是一个示例类,以及一个示例对象列表:
class Sample(object):
def __init__(self, name, sampleValue1, sampleValue2):
self.name
self.value1 = sampleValue1
self.value2 = sampleValue2
def __repr__(self):
return self.name
# creating sample objects for clarification
objectNames = ['A','B','C','D']
values1 = [3,4,1,2]
values2 = [1,4,2,3]
sampleObjects = list()
for i in xrange(4):
obj = Sample(objectNames[i], values1[i], values2[i])
sampleObjects.append(obj)
Sorting sampleObjects from each of the objects values should yield what's below. 从每个对象值中对sampleObject进行排序应该产生以下内容。 Sorting should return a list of the objects in the order specified (objects names are used below).
排序应按指定的顺序返回对象列表(下面使用对象名称)。
value1: [C,D,A,B]
value1 reversed: [B,A,D,C]
value2: [A,C,D,B]
value2 reversed: [B,D,C,A]
Python built-in sorted
function has signature: Python内置的
sorted
函数有签名:
sorted(iterable[, cmp[, key[, reverse]]])
and 和
key specifies a function of one argument that is used to extract a comparison key from each list element
key指定一个参数的函数,该函数用于从每个列表元素中提取比较键
For your case: 对于你的情况:
>>> sorted(sampleObjects, key=lambda obj: obj.value1)
[C, D, A, B]
>>> sorted(sampleObjects, key=lambda obj: obj.value2)
[A, C, D, B]
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