PHP表单更新mysql数据库在编辑一条记录后返回所有数据库记录

Question

so I have this code that other Stack members have helped me fine tune and correct some errors, the code all works as it should but there is one small detail, after successfully editing one record and clicking the update button ALL of the existing records that are in the database load into the page. Here is my code below:

<?php 

$con = mysql_connect("localhost", "root", "M1q2w3e4r");
if (!$con) {
die("Can not connect: " . mysql_error());
}
mysql_select_db("inventory",$con);

if (isset($_POST['update'])){
$UpdateQuery = "UPDATE invoice SET `inv_number`='$_POST[inv_number]', `from_date`='$_POST[from_date]', `to_date`='$_POST[to_date]',`date_type`='$_POST[date_type]', `notes`='$_POST[notes]' WHERE id='$_POST[id]'";               
mysql_query($UpdateQuery, $con);
};

$where = '';
    if(!empty($_GET) && !empty($_GET['edit'])) {
        $where = ' where id='.$_GET['edit'];
    }
    $sql = "SELECT * FROM invoice".$where;

$myData = mysql_query($sql,$con);
echo "<table border=1>
<tr>
<th>Inv #</th>
<th>From</th>
<th>To</th>
<th>Type</th>
<th>Notes</th>
</tr>";
while($record = mysql_fetch_array($myData)){
echo "<form action='edit.php' method='post'>";
echo "<tr>";
echo "<td>" . "<input type='text' name='inv_number' value='" . $record['inv_number'] . "'> </td>";
echo "<td>" . "<input type='text' id='from' name='from_date' value='" . $record['from_date'] . "'> </td>";
echo "<td>" . "<input type='text' id='to' name='to_date' value='" . $record['to_date'] . "'> </td>";
echo "<td>" . "<input type='text' name='date_type' value='" . $record['date_type'] . "'> </td>";
echo "<td>" . "<input type='text' name='notes' value='" . $record['notes'] . "'> </td>";
echo "<td>" . "<input type='hidden' name='id' value='" . $record['id'] . "'> </td>";
echo "<td>" . "<input type='hidden' name='hidden' value='" . $record['id'] . "'> </td>";
echo "<td>" . "<input type='submit' name='update' value='update'>" . " </td>";
echo "</tr>";
echo "</form>";
}

echo "</table>";
mysql_close($con);

?>

I know it has to do with the form action="edit.php", as it refreshes the page the id number in the url is pulled out. So I tried this:

echo "<form action='edit.php?edit=<?php echo $_REQUEST["id"]; ?>' method='post'>";

but this only led to my edit.php to display as a blank page. If anyone can help me figure out how to prevent all the database records from being displayed in the page after clicking the update button it would really help.

Answer 1

I might do this, for example, if I just wanted to show the record that was just updated:

if (isset($_POST['update'])){
    $UpdateQuery = "UPDATE invoice SET `inv_number`='$_POST[inv_number]',    `from_date`='$_POST[from_date]', `to_date`='$_POST[to_date]',`date_type`='$_POST[date_type]', `notes`='$_POST[notes]' WHERE id='$_POST[id]'";               
    mysql_query($UpdateQuery, $con);
    $where = ' where id='.$_POST[id];
}
else {
    $where = '';
    if(!empty($_GET) && !empty($_GET['edit'])) {
        $where = ' where id='.$_GET['edit'];
    }
}

You could also use REQUEST instead of GET and make a hidden input field with the name "edit" in your form.