PHP-从函数返回数组

Question

I am submitting a form, using the following function (prize.php) :

loadmodule('validate'); //This just loads the validate.php function.
    $validate = new Validate;
if($_POST)
    {
        $validateForm = $validate->validateForm();


        switch($validateForm)
        {

                case 1:
                    $error = 'You\'re not logged in..';
                    $stop = true;
                break;

                //If no error = success.    
                if($validateForm['code'] == "100"){
                    $won = $val['prize'];
                    $type = $val['type'];
                    $success = 'You have won! The prize was '.$won.' '.$type.'';
                    die($success);
                }


        }
            die($error);
    }

This is the function to validate the form (validate.php) :

function validate()
                {


                    global $userdata;

                    if(!is_array($userdata))
                        return 1; // User not logged in - return error code one.

                    //If no error, lets show a success message.
                    $prize = "100";
                $text = "dollars";
                    return array("code"=>"100","prize"=>"$prize","type"=>"$text");

                    }//If won



                }

The above code returns:

Notice: Undefined variable: error in /home/.../public_html/pages/prize.php on line 27

Although, it shouldn't throw an error there, since the die($success) should be triggered by the code 100.

What am I doing wrong?

Answer 1

$error = '';
$stop = false;
switch($validateForm){
            case 1:
                $error = 'You\'re not logged in..';
                $stop = true;
            break;
}


            //If no error = success.    
            if($validateForm['code'] == "100"){
                $won = $val['prize'];
                $type = $val['type'];
                $success = 'You have won! The prize was '.$won.' '.$type.'';
                die($success);
            }

first guess is that the if($validateForm['code'] == "100"){ is ment to be outside the switch.

$validateForm = $validate->validateForm();

returns an array.. later on your're doing a if ($validateForm==1) in the switch.. when $validateForm is an array.

you might have better luck with a simple is_array() if statement than the whole switch