迭代列表列表并在这些列表中查找连续的数字

Question

currently I am trying to find consecutive numbers in a nested list. My goal is the following example:

nested = [ [1,7,13], [2,5,8], [3, 6, 9] ]

OUTPUT : (1,2,3), (7,8,9)

It should also work if there are more than three lists. The amount of lists can vary.

(Background for this; i am building a search engine for school and the numbers in nested are positions of the query words given by a user.)

I have used :

def is_coherent(x):
    return all(np.diff(x) == 1)

to see if integers are consecutive. Also i have experimented with itertools.izip. However this does not allow me to change in the amount of lists i would like to iterate through.

Any help would be greatly appreciated!

Answer 1

I think you want to get those items from cartesian product of the inner lists whose all items are continuous, for that you can try something like this:

from itertools import izip, product

def find_continuous_items(data):
    for p in product(*data):
        if all(b-a==1 for a, b in izip(p, p[1:])):
            yield p

nested = [[1,7,13], [2,5,8], [3, 6, 9]]
print list(find_continuous_items(nested))
#[(1, 2, 3), (7, 8, 9)]