[英]Why iOS 8.0 simulator in Xcode 6.0.1 could not fetch cookie correctly
After upgrade to Xcode 6, When I fetch cookies from a login "POST" action, like this: 升级到Xcode 6之后,当我通过登录“ POST”操作获取Cookie时,如下所示:
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://%@/login.php", kDSZHDomainString]];
ASIFormDataRequest *asirequest = [ASIFormDataRequest requestWithURL:url];
[asirequest setPostValue:username forKey:@"u"];
[asirequest setPostValue:password forKey:@"p"];
[asirequest setTag:kLoginRequest];
[asirequest setStringEncoding:-2147481083];
[asirequest setTimeOutSeconds:600];
[asirequest setDelegate:self];
[asirequest startAsynchronous];
when I set breakpoint to get request's headers: 当我设置断点以获取请求的标头时:
NSMutableDictionary * headers = [request requestHeaders];
debug info: 调试信息:
Printing description of headers:
{
"Accept-Encoding" = gzip;
"Content-Length" = 20;
"Content-Type" = "application/x-www-form-urlencoded; charset=hz-gb-2312";
Cookie = "__utma=213790228.284667840.1411460847.1411460847.1411460847.1; __utmz=213790228.1411460847.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); o=m; s=542366a13a44e; sv[1]=12532852%2C12532147%2C12534523; v[11]=12515374; v[1]=12534523; v[2]=12521992; v[3]=12527199; v[9]=12441637";
"User-Agent" = "Top81 0.7 rv:0.7.459 (iPhone Simulator; iPhone OS 8.0; en_US)";
}
In iOS 7 simulator, headers are: 在iOS 7模拟器中,标头为:
Printing description of headers:
{
"Accept-Encoding" = gzip;
Cookie = "o=m; s=542369d4ede78; sv[1]=12532886%2C12528442%2C12534551; u=xxxx%2Ca999b1c0d3663e236f58277302b8be90%2C0; v[1]=12534551";
"User-Agent" = "Top81 0.7 rv:0.7.459 (iPhone Simulator; iPhone OS 7.1; en_US)";
}
so, cookie "u" fetched correctly. 因此,cookie“ u”正确获取。
I test the code with ASIHTTPRequest and AFNetworking, and get same result. 我使用ASIHTTPRequest和AFNetworking测试代码,并得到相同的结果。
Is it the Xcode and iOS 8 simulator's bug or any code to resolve this problem? 是Xcode和iOS 8模拟器的bug还是解决此问题的任何代码?
I have used afnetworking and it is working fine in ios 8. Here's the function 我已经使用过afnetworking,并且在ios 8中工作正常。这是功能
+(void)postData : (NSString *)url parameters:(NSDictionary *)paraDict success: (void (^) (NSDictionary *responseStr))success failure: (void (^) (NSError *error))failure
{
AFHTTPRequestOperationManager *manager = [[AFHTTPRequestOperationManager alloc] initWithBaseURL:[NSURL URLWithString:url]];
manager.responseSerializer = [AFHTTPResponseSerializer serializer];
AFHTTPRequestOperation *op = [manager POST:url parameters:paraDict constructingBodyWithBlock:^(id<AFMultipartFormData> formData) {
} success:^(AFHTTPRequestOperation *operation, id responseObject)
{
NSError* error = nil;
success([NSJSONSerialization JSONObjectWithData:responseObject options:0 error:&error]);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
failure(error);
}];
[op start];
}
Here url is string not nsurl which should be like @" http://www.google.com " 此处的url是不是nsurl的字符串,应类似于@“ http://www.google.com ”
and paradict is dictionary.U can make it like 参数是字典。U可以使它像
NsDictionary *paraDict = @{@"username":@"u",@"password":@"p"} NsDictionary * paraDict = @ {@“用户名”:@“ u”,@“密码”:@“ p”}
Hope it helps 希望能帮助到你
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