回应PHP预备语句的最有效方法

Question

I have an SQL query which I have recently turned into a prepared statement for security purposes. I have a query which returns many rows, each consisting of many columns. My question is how to echo the results using a while loop. My example I have so far:

$stmt = $conn->prepare("SELECT * FROM Customers 
                                  WHERE travel_Date >= ?
                                  AND   travel_Date <= ?
                                  ".$searchOption."
                                  LIMIT ? 
                                  OFFSET ?");
$todayDateFrom = $todayDate." 00:00:00";
$todayDateTo = $todayDate." 23:59:59";
$stmt->bind_param("ssii", $todayDateFrom, $todayDateTo, $limit, $offset);
$stmt->execute();

while ($stmt->fetch()) {
    //echo first name
    //echo surname
    //echo address
    //echo number
    //echo type
    //15 other things i need to print off
}

I'm not sure what the best way to do this is. I have thought about:

$stmt->bind_result($firstName, $surname, $address, //etc);

But I'm wondering if there's another alternative similar to unprepared statements:

while($row = mysqli_fetch_array($query)){
    echo $row['firstName'];
    echo $row['surname'];
    echo $row['address'];
    //etc
}

Answer 1

try this:

$result = $stmt->get_result();
    while ($row = $result->fetch_array())
    {
        echo $row['firstName'];
        echo $row['surname'];
        echo $row['address'];
    }

Answer 2

try this -

$result_arr = array();
while($row = $stmt->fetch()){
  $record = array();
  $record['firstname'] = $row['firstname']; // if your db column contains firstname column other wise you can also use $row[0];
  $record['name'] = $row[1]; // end so on .......
  $result_arr[] = $record;
}

hope this will work for u...