在Java中以逗号分隔字符串

Question

I have a string with an unknown length that looks like this

a ,b, c: integer; d,e :real;

How could I split this at the commas without getting the words and characters that follow the last commas of the variables? Or is there a way to split the variables at the commas after it is in an array from splitting at the colon? The closest I have come is with this method

// the variablesArray would contain a ,b,  c in the first index
// and d,e in the second index.
public static String[] variables(String[]variablesArray) { 
    String variables[] = new String[variablesArray.length];

    for(int i = 0; i < variablesArray.length; i++){
        String temporary = variablesArray[i];
        String arr[] = temporary.split(",");
    }
    return variables;
}

When I run this it only returns the first character in the array index

//prints [ad]

Answer 1

You'll need to break the problem up:

• Split the string at ; .
• For each of the words you got:
  • Split the string at :
  • Insert the first part (list of variable names) into your array.
  • Throw away the second part (type information).

Note that this will give you the array {"a ,b, c", "d,e"} as I understand from your question that you want it. If you want to split that further, you'll need to split each of these strings again , this time at , . Note that you'll need to change the type of your array from String[] to String[][] in this case. You'll get {{"a", "b", "c"}, {"d", "e"}} .

If you also want to strip whitespace during the process of splitting, add \\s* before and after the split character. For example: "a, b,c , d".split("\\\\s*,\\\\s*") returns {"a", "b", "c", "d"} .

Answer 2

if myString is equal to "a ,b, c: integer; d,e :real;" the following with output abcde

for (String type : myString.split(";")) {
  String sub = type.substring(0, type.indexOf(":"));
  for (String name : sub.split(",")) {
    System.out.println(name);
  }
}

Answer 3

I think you have a problem. temporary.split(","); is an array then you have appened it to be as a part of another array. Thats troublesome .... I mean:

Array
     0 => Array
               0 => a  
               1 => b

So you should use:

String arr = temporary.split(",");

Answer 4

how about following?

public static void main(String[] args) {
    List<String> list = new ArrayList<String>();
    String str = "a ,b,c: integer;d,e :real;";
    String[] stra = str.split(";");
    for(String st: stra){
        //System.out.println(st);
        String[] stra2 = st.split(",");
        for(String s: stra2){
            System.out.println(s);
            list.add(String.valueOf(s.charAt(0)));
        }
    }
    System.out.println(list);
}

OP

a 
b
c: integer
d
e :real
[a, b, c, d, e]

Answer 5

is this what you want?

String[] result = s.replaceAll("\\w{2,}", "").replaceAll("[:;,]"," ").replaceAll("\\u0020+"," ").split(" ");

Array result now holds only the single chars. Testing with:

for(String c: array)
        System.out.println(c);

will output:

a
b
c
d
e