[英]How to make tree menu with css, mysql and codeigniter
i wanna make dynamic tree menu using css and codeigniter. 我想使用CSS和Codeigniter制作动态树菜单。 here is table of cmb_menu:
这是cmb_menu的表:
(`id_menu`, `id_parent`, `menu`)
(1, '0', 'see and do')
(2, '0', 'travel info')
(3, '0', 'inside dublin')
(4, '1', 'event')
(5, '1', 'tour')
(6, '2', 'tips')
and i use this function to get normal result. 我用这个功能来得到正常的结果。 and it works.
而且有效。
function menu($parent=0,$hasil){
$w = $this->db->query("SELECT * from cmb_menu where id_parent='".$parent."'");
if(($w->num_rows())>0)
{
$hasil .= "<ul>";
}
foreach($w->result() as $h)
{
$hasil .= "<li>".$h->menu;
$hasil = $this->menu($h->id_menu,$hasil);
$hasil .= "</li>";
}
if(($w->num_rows)>0)
{
$hasil .= "</ul>";
}
return $hasil;
}
but i get a problem when using it and i have no idea how to customize that function so i can get the result. 但是我在使用它时遇到了一个问题,我也不知道如何自定义该功能,以便获得结果。 like this:
像这样:
<ul class="menu span9 inline">
<li class="dropdown-submenu">
<a href="travel.html">see and do</a>
<ul class="dropdown-menu">
<li><a href="">Highlights</a></li>
<li class="dropdown-submenu">
<a href="">Activities</a>
<ul class="dropdown-menu">
<li><a href="">Traditional</a></li>
<li><a href="">Shopping</a></li>
<li><a href="">Cafes</a></li>
<li><a href="">Restaurants</a></li>
</ul>
</li>
<li><a href="">Events</a></li>
<li><a href="">Tour & Attractions</a></li>
</ul>
</li>
<li class="dropdown-submenu">
<a href="travel.html">where to stay</a>
<ul class="dropdown-menu">
<li><a href="">Hotel</a></li>
<li><a href="">Homestay</a></li>
<li><a href="">Guesthouse</a></li>
</ul>
</li>
<li><a href="fashion.html">inside minangkabau</a></li>
<li><a href="travel.html">travel info</a></li>
<li class="dropdown-submenu">
<a href="fashion.html">articles</a>
<ul class="dropdown-menu">
<li><a href="">Tips</a></li>
<li><a href="">Offers</a></li>
<li><a href="">Minangkabau</a></li>
<li><a href="">Culture</a></li>
<li><a href="">Food & Drink</a></li>
</ul>
</li>
<li><a href="travel.html">map</a></li>
</ul>
MySQL isn't able to execute recursive queries. MySQL无法执行递归查询。 You have two choices :
您有两种选择:
Then you just have to call it by passing to it the parent id and iterate on the resulting rows (each row is a node and the second column is the list of ids of the children nodes). 然后,您只需通过将其传递给父ID并对其进行迭代就可以对其进行调用(每行是一个节点,第二列是子节点的ID列表)。 You can change the code of the function so as to add more information.
您可以更改功能代码,以添加更多信息。
DELIMITER $$
DROP FUNCTION IF EXISTS `GetFamilyTree` $$
FUNCTION `GetFamilyTree`(`GivenID` INT) RETURNS varchar(1024) CHARSET latin1
DETERMINISTIC
BEGIN
DECLARE rv,q,queue,queue_children VARCHAR(1024);
DECLARE queue_length,front_id,pos INT;
SET rv = '';
SET queue = GivenID;
SET queue_length = 1;
WHILE queue_length > 0 DO
SET front_id = FORMAT(queue,0);
IF queue_length = 1 THEN
SET queue = '';
ELSE
SET pos = LOCATE(',',queue) + 1;
SET q = SUBSTR(queue,pos);
SET queue = q;
END IF;
SET queue_length = queue_length - 1;
SELECT IFNULL(qc,'') INTO queue_children
FROM (SELECT GROUP_CONCAT(id) qc
FROM cmb_menu WHERE id_parent = front_id) A;
IF LENGTH(queue_children) = 0 THEN
IF LENGTH(queue) = 0 THEN
SET queue_length = 0;
END IF;
ELSE
IF LENGTH(rv) = 0 THEN
SET rv = queue_children;
ELSE
SET rv = CONCAT(rv,',',queue_children);
END IF;
IF LENGTH(queue) = 0 THEN
SET queue = queue_children;
ELSE
SET queue = CONCAT(queue,',',queue_children);
END IF;
SET queue_length = LENGTH(queue) - LENGTH(REPLACE(queue,',','')) + 1;
END IF;
END WHILE;
RETURN rv;
END$$
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