如何计数和打印一次？

Question

My file has 6 rows of integers

For example my file name is abc.txt it has following input

12 13
13 1000
12 -58
8 4 

I added the inputs like this 12+13 , 13+1000 etc etc and took average of them

I want to count and print how many times the average was inside 0-10 that is more than 0 and less than10

From my example it should print more than 0 and less than 10 = 2

I intiated count = 0 at the beginning and run this code

if(avg >=0 && avg<10){
    count++;
    System.out.println ("more than 0 and less than 10 = "+count);
}

But it prints

more than 0 and less than 10 = 1
more than 0 and less than 10 = 2

How can I make it prints once so that the output will only be like

more than 0 and less than 10 = 2

Answer 1

just put System.out.println ("more then 0 and less then 10 = "+count); out of your looping code when reading the lines in the file. For example:

......
Looping...
do count++ if avg >=0 && avg<10;
End Loop..

print it by System.out.println ("more then 0 and less then 10 = "+count);

Hope it helps and answered your question.

Answer 2

let me try and help u by listing some of the steps for ur problem.

First while scanning the numbers, put them into an array. While ur putting the numbers in the array , sum it up. This will help u to give the sum result at the end of it. After that take the average of the number by deviding with the array count.(This will help u save memory by preventing unnecessary variable creation.

After that use the array and if else logic to achieve ur end result.

Also for the error that ur getting I guess ur printing it inside a loop.