[英]How can I append <DIV> tag which cames from AJAX?
I am new for the Ajax and I am working on the application which provide employee salary as per user input value. 我是Ajax的新手,正在开发按用户输入值提供员工薪水的应用程序。
Now, My question is I am trying to get the data from Ajax in that I wish to display that portion at particular place on my main page 现在,我的问题是我想从Ajax获取数据,因为我希望在主页的特定位置显示该部分。
Let me explain you what I am actually asking for, please have a look: 让我向您解释我的实际要求,请看一下:
<div id=main>
<div id=1st>
</div>
<div id=2nd>
</div>
</div>
<div>
<div id=display_result>
</div>
</div>
above is the sample and I am passing data of id=2nd div & id=display_result div tags which belongs from two different class of CSS and as their own separate position. 上面是示例,我正在传递id = 2nd div和id = display_result div标签的数据,它们分别来自两个不同的CSS类,并作为它们各自的位置。
Here is the actual code in which I am facing the problem. 这是我面临问题的实际代码。
<div id="find_max_div" class="table-div select-table" style="width:95% !important;">
<div style="text-align:right;">
<img width="30px" src="MaxVal_image/close.png" style="margin-right:20px;" class="mousepointer" title="close" name="close1" id="close1">
</div>
<div style="display:flex;">
<div class="position-div-left row_th">
<div class="position-left"> Enter position: </div>
<div class="position-right">
<input type="text" size="40" name="position" id="position" placeholder="Enter position" class="textbox">
</div>
</div>
<div class="position-div-right row_th" id="same_emp_sal_list-div">
<div class="position-left"> Select Employee: </div>
<div class="position-right">
<select name="same_sal_emp_list" id="same_sal_emp_list" class="textbox">
</select>
</div>
</div>
</div>
<div id="max_result_table" style="margin-top:12px;">
</div>
</div>
I am passing the data from: 我从传递数据:
<div class="position-div-left row_th">
<div class="position-left"> Enter position: </div>
<div class="position-right">
<input type="text" size="40" name="position" id="position" placeholder="Enter position" class="textbox">
</div>
</div>
Try below :- 请尝试以下:-
<div class="result"></div>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>
function refresh_div() {
jQuery.ajax({
url:'YOUR PHP page url',
type:'POST',
success:function(results) {
jQuery(".result").html(results);
}
});
}
</script>
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