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为什么System.out.println()可以解决我的Hibernate Session?

[英]Why System.out.println() can solving my Hibernate Session?

Hello I'm newbie in learning hibernate framework. 您好,我是学习休眠框架的新手。 I was solved my error but I don't know what the problem happen. 我已经解决了我的错误,但是我不知道发生了什么问题。 In my project I have 2 tables Tblbarang and Tbljenis . 在我的项目中,我有2张桌子TblbarangTbljenis And 1 field at Tblbarang had relations as foreign key by Tbljenis . 并且TblbarangTblbarang 1个字段具有作为外键的Tbljenis

I want to update Tblbarang table. 我想更新Tblbarang表。 I had two method 我有两种方法

private void getcombobarang() {
    Query q = sess.createQuery("from Tblbarang");
    arrbarang = new ArrayList<>();

    DefaultComboBoxModel comboModel = new DefaultComboBoxModel();

    for (Object o : q.list()) {
        Tblbarang coba = (Tblbarang) o;
        comboModel.addElement(coba.getNamabarang());
        arrbarang.add(coba);
    }
    combobarang.setModel(comboModel);
}

This method to set model combobox which I would choose to set the table Tblbarang item. 这种设置模型组合框的方法,我会选择设置表Tblbarang项。

and now this method to update my Table Tblbarang 现在这个方法来更新我的表Tblbarang

sess = NewHibernateUtil.getSessionFactory().openSession();
sess.beginTransaction();
Tblbarang tb = new Tblbarang();
tb.setKodbarang(arrbarang.get(combobarang.getSelectedIndex()).getKodbarang());
tb.setNamabarang(arrbarang.get(combobarang.getSelectedIndex()).getNamabarang());
tb.setTbljenis(arrbarang.get(combobarang.getSelectedIndex()).getTbljenis());
tb.setHarganet(arrbarang.get(combobarang.getSelectedIndex()).getHarganet());
tb.setHargajual(arrbarang.get(combobarang.getSelectedIndex()).getHargajual());
System.out.println(arrbarang.get(combobarang.getSelectedIndex()).getTbljenis()); // <-- this line resolved my problem
int st = Integer.parseInt(stok.getText()) ;
int jm = Integer.parseInt(jumlah.getText());
String totss = String.valueOf(st + jm);
Short totstok = Short.parseShort(totss);
tb.setStok(totstok);
sess.update(tb);
sess.getTransaction().commit();

when without System.out.print() the error are following 没有System.out.print()出现以下错误

org.hibernate.HibernateException: illegally attempted to associate a proxy with two open Sessions
at org.hibernate.proxy.AbstractLazyInitializer.setSession(AbstractLazyInitializer.java:126)
at org.hibernate.proxy.AbstractLazyInitializer.setSession(AbstractLazyInitializer.java:126)
at org.hibernate.engine.StatefulPersistenceContext.reassociateProxy(StatefulPersistenceContext.java:573)
at org.hibernate.engine.StatefulPersistenceContext.reassociateIfUninitializedProxy(StatefulPersistenceContext.java:533)
at org.hibernate.event.def.ProxyVisitor.processEntity(ProxyVisitor.java:50)
at org.hibernate.event.def.AbstractVisitor.processValue(AbstractVisitor.java:125)
at org.hibernate.event.def.AbstractVisitor.processValue(AbstractVisitor.java:83)
at org.hibernate.event.def.AbstractVisitor.processEntityPropertyValues(AbstractVisitor.java:77)
at org.hibernate.event.def.AbstractVisitor.process(AbstractVisitor.java:144)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.performUpdate(DefaultSaveOrUpdateEventListener.java:314)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.entityIsDetached(DefaultSaveOrUpdateEventListener.java:246)
at org.hibernate.event.def.DefaultUpdateEventListener.performSaveOrUpdate(DefaultUpdateEventListener.java:57)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:93)
at org.hibernate.impl.SessionImpl.fireUpdate(SessionImpl.java:742)
at org.hibernate.impl.SessionImpl.update(SessionImpl.java:730)
at org.hibernate.impl.SessionImpl.update(SessionImpl.java:722)
at retail.ui.frmBarangMasuk.tambahitemActionPerformed(frmBarangMasuk.java:622) //<-this line directing to sess.update(tb)

I will simply my code like this 我将像这样简单地编写我的代码

sess = NewHibernateUtil.getSessionFactory().openSession();
sess.beginTransaction();
Tblbarang tb = (Tblbarang) arrbarang.get(combobarang.getSelectedIndex());
System.out.println(arrbarang.get(combobarang.getSelectedIndex()).getTbljenis());
int st = Integer.parseInt(stok.getText()) ;
int jm = Integer.parseInt(jumlah.getText());
String totss = String.valueOf(st + jm);
Short totstok = Short.parseShort(totss);
tb.setStok(totstok);
sess.update(tb);
sess.getTransaction().commit();

but the exception showing same error. 但异常显示相同的错误。 I want to know what happen with my code? 我想知道我的代码会怎样? anyone can explain with that issue or this is bug from hibernate, thanks 任何人都可以解释这个问题,或者这是来自休眠的错误,谢谢

In getcombobarang , you have a sess (session1) to get objects from database. getcombobarang ,您有一个sess (session1)从数据库中获取对象。 And when updating tb , you open another sess (session2). 当更新tb ,您打开另一个sess (session2)。

If Tblbarang contains a foreign-key object, in this case, which must associates with session1 , because it's obtained from the function getcombobarang at first. 如果Tblbarang包含一个外键的对象,在这种情况下,必须与会话1关联,因为它从功能上获得getcombobarang在第一。 So sess.update() throws an exception as you have seen. 因此,如您所见, sess.update()引发异常。

For solution: 解决方案:

  1. use merge() instead of update() 使用merge()而不是update()
  2. before update, copy the foreign-key object's properties to a whole new object, then set it into tb 在更新之前,将外键对象的属性复制到一个全新的对象中,然后将其设置为tb

I'm also confused about the impact of System.println() here. 我也对System.println()的影响感到困惑。

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