[英]Handling select box values using HTML jQuery
I have a code like this. 我有这样的代码。
HTML: HTML:
<select id="from_value">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
<select id="to_value">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
JQuery: jQuery的:
$("#from_value").change(function () {
var val = +this.value;
$("#to_value option").hide();
$("#to_value option:gt(" + val + "),#to_value option:eq(" + val + ")").show();
$("#to_value").val(val);
});
The code is shared in jsfiddle for easy editing. 该代码在jsfiddle中共享,以便于编辑。 http://jsfiddle.net/fuub1wrd/1/
http://jsfiddle.net/fuub1wrd/1/
When the from value is changed, the to value is getting changed based on from_value event. 当from值更改时,基于from_value事件更改to值。
Now, what I'm trying to do is. 现在,我想做的是。
If the from_value
is 5
, then the to_value
should display 5,6,7,8
only (only four values from the selected value) 如果
from_value
为5
,则to_value
应该仅显示5,6,7,8
(所选值中只有四个值)
In other words, display only four values with respect to the from_value. 换句话说,相对于from_value仅显示四个值。 If
from_value
is 6
, then in to_values
i should be able to see only 6,7,8,9
如果
from_value
是6
,那么在to_values
我应该只能看到6,7,8,9
How can I achieve that? 我该如何实现? I know this is bit easy, but still, I'm sitting with my code.
我知道这有点容易,但是仍然坐在我的代码旁。
Thanks, Kimz 谢谢,金兹
Try this... 尝试这个...
$("#from_value").change(function () {
var val = +this.value;
$("#to_value option")
.hide()
.filter(function() {
return ($(this).val() >= val && $(this).val() < val + 4);
})
.show();
$("#to_value").val(val);
});
http://jsfiddle.net/fuub1wrd/4/ http://jsfiddle.net/fuub1wrd/4/
It hides all the options and then uses the filter()
function in order to identify the options you want to show. 它隐藏了所有选项,然后使用
filter()
函数来标识要显示的选项。
Try this: 尝试这个:
HTML: HTML:
<select id="from_value">
<option value="0">select</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
<select id="to_value">
<option value="0">select</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select>
Jquery : jQuery的:
$("#from_value").change(function () {
var val = +this.value;
$("#to_value option").removeAttr('disabled');
$("#to_value option:lt(" + val + ")").attr('disabled','disabled');
});
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