PHP多维数组排序

Question

Edit : I need it to do only in Array Sort, As i am using procedure and sending it into json,

Here is my Table Structure,

SQL Fiddle

I want to display as

2. alpha london
3. alpha newyork
4. beta delhi
5. beta sydney

I mean, the second coloumn (name) should be in Ascending Order and the third coloumn (place) should be in Descending Order.

How i want is

1. alpha london
2. alpha newyowk
3. beta delhi
4. beta sydney

The Name should be in Asc Order and then to the right, the Place should be in Desc Order

What i have tried so far is

How can i do this ??

<?php
include ('conn.php');
$sql="SELECT * FROM test";
$result=mysql_query($sql);
$rows=mysql_fetch_array($result);
while($rows=mysql_fetch_array($result))
{
foreach($result as $k=>$v)
{
echo $k;

}
}
?>

It displays the result as Invalid argument supplied to for each. What is the mistake i am doing and how can achieve my output

Answer 1

To fix the sorting, just add ORDER BY name, place

Then there's several more issues preventing this from working:

1. You shouldn't call mysql_fetch_array outside the loop (this would discard the first row, alpha london in your example).
2. You need to iterate over $rows , not $result (this is where the "invalid argument" error is coming from).
3. You're not echoing the value; only the key. So you wouldn't be displaying the name and place at all; only the words "name" and "place".

You might want to do something like this to fix these:

<?php
include('conn.php');
$sql = "SELECT * FROM test ORDER BY name, place";
$result = mysql_query($sql);
while ($rows = mysql_fetch_array($result)) {
  foreach ($rows as $k => $v) {
    echo "$k is $v. ";
  }
  echo "<br/>";
}
?>

Answer 2

那么，为什么不像这样在查询中进行订单

SELECT * FROM test order by name;

Answer 3

You can do this only modifying query.

Use this query:

SELECT * FROM test ORDER BY name ASC, place DESC

Answer 4

For your error, you are using wrong variable as foreach. Replace this -

foreach($result as $k=>$v)
{
    echo $k;
}

with this -

foreach($rows as $k=>$v)
{
    echo $k;
}

Buy why are using foreach inside while loop. You can get your values like -

while($rows = mysql_fetch_array($result)) {
    echo $rows['name'].' '.$rows['place'].'<br/>';
}

and don't use mysql_* function. Use instead mysqli_*

And for your expected output, try using following query -

SELECT * FROM `test` order by name asc, place desc

Answer 5

This is the kind of thing you can fix using array_multisort. Try the below example (which I have not tested yet, but ought to work)

<?php
include ('conn.php');
$sql="SELECT * FROM test";
$result=mysql_query($sql);

$totals = array();
$row = array();
$places = array();
while($row=mysql_fetch_array($result)){
    $totals[] = $row
    $names[] = $row['name'];
    $places[] = $row['place'];
}
array_multisort( $names, SORT_ASC, $places, SORT_DESC, $totals );

// now you can use $totals, which is sorted as you want
print_r( $totals );