为什么不休息

Question

My code below is from Oracle.

public class MyLoop {
  public static void main(String[] args) { 
    String[] sa = {"tom ", "jerry "}; 
    for(int x = 0; x < 3; x++) {
      for(String s : sa) {
        System.out.print(x + " " + s);
        if(x == 1) break; 
      }
    }
  }
}

Output:

 0 tom 0 jerry 1 tom 2 tom 2 jerry 

I am learning java and I came across this. I don't understand why 1 tom prints when the break is at 1 . If 1 tom prints why then doesn't 1 jerry ?

Answer 1

对于x每个值，您正在打印表sa的全部内容，但x == 1除外，其中仅打印sa的第一个值：打印此值后，您要检查x == 1以及然后离开内部循环并继续x的下一个值。

Answer 2

First check "x == 1" then print.

String[] sa = { "tom ", "jerry " };
for (int x = 0; x < 3; x++) {

    for (String s : sa) {
        if (x == 1) {
          break;
        }
        System.out.print(x + " " + s);

     }
}