[英]Sql Query with time interval
I want to get best 3 day of users between "2014-07-01" and "2014-08-01" 我希望在“ 2014-07-01”和“ 2014-08-01”之间获得最佳的3天用户
Could someone help me? 有人可以帮我吗? I've been stuck here for 3 days. 我已经在这里停留了三天。
In real score table entries are 10:00 to 22:00 and 1 entries for each hour. 在实际分数表中,条目为10:00到22:00,每小时1个条目。
Total of 12 entry for each day and each player (sometimes it could be less 1 or 2). 每天和每个玩家总共有12个条目(有时可能少于1或2)。
This is the output I'm trying to get: 这是我想要获得的输出:
ID | User_ID | Username | Sum(Score) | Date
--------------------------------------------------
1 | 1 | Xxx | 52 | 2014-07-01
2 | 1 | Xxx | 143 | 2014-07-02
3 | 2 | Yyy | 63 | 2014-07-01
...
Score
table: Score
表:
ID | User_ID | Score | Datetime
-----------------------------------------
1 | 1 | 35 | 2014-07-01 11:00:00
2 | 1 | 17 | 2014-07-01 12:00:00
3 | 2 | 36 | 2014-07-01 11:00:00
4 | 2 | 27 | 2014-07-01 12:00:00
5 | 1 | 66 | 2014-07-02 11:00:00
6 | 1 | 77 | 2014-07-02 12:00:00
7 | 2 | 93 | 2014-07-02 12:00:00
...
User
table : User
表:
ID | Username
--------------
1 | Xxx
2 | Yyy
3 | Zzz
...
I think you need to aggregate first by date, and then choose the first three using row_number()
. 我认为您首先需要按日期进行汇总,然后使用row_number()
选择前三个。 To do the aggregation: 要进行聚合:
select s.user_id, sum(s.datetime, 'day') as theday, sum(score) as score,
row_number() over (partition by s.user_id order by sum(score) desc) as seqnum
from scores s
group by s.user_id;
To get the rest of the information, use this as a subquery or CTE: 要获取其余信息,请将其用作子查询或CTE:
select u.*, s.score
from (select s.user_id, sum(s.datetime, 'day') as theday, sum(s.score) as score,
row_number() over (partition by s.user_id order by sum(s.score) desc) as seqnum
from scores s
group by s.user_id
) s join
users u
on s.user_id = u.users_id
where seqnum <= 3
order by u.user_id, s.score desc;
SELECT 'group has no id' as ID,
u.ID as User_ID,
u.Username,
sum(s.Score) "Sum(Score)",
s.Datetime::date as Date
FROM User u,
Score s
WHERE u.id = s.User_ID
AND s.Datetime BETWEEN '2014-07-01' AND '2014-08-01 23:59:59'
GROUP BY u.ID, u.Username, s.Datetime::date
ORDER BY sum(s.Score) DESC
LIMIT 3;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.