awk +运行awk命令而不从管道输出

Question

the target of the following code is to verify if the free memory is less then 20% of the total memory

in case fr ee memory less then awk should print FAIL otherwise awk will print ok

TOTALM=120000K
FREEM=89111K

please advice what wrong in this syntax? , why I cant run awk as displayed here?

awk -v FREEM=$FREE_MEMORY -v TOTALM=$TOTAL_MEMORY '{per=int(FREEM)/int(TOTALM)*100; if(per<=20) print "FAIL" ; else print "OK"}'  

Answer 1

You have a couple of problems in your code:

Firstly, you have changed the names of your two variables when passing them into awk .

Secondly, awk needs an input file after the script, but you can get around that requirement by putting your code inside a BEGIN block.

#!/bin/bash
TOTALM=120000K
FREEM=89111K
awk -v FREEM=$FREEM -v TOTALM=$TOTALM '
           BEGIN {per=int(FREEM)/int(TOTALM)*100
                  if(per<20) print "FAIL"
                  else print "OK"}'