在C ++中将N位int表示为十六进制

Question

I've a number between 0 and 63, so max 6 bits.
Then I've to represent this number in hexadecimal.

How can I force the reresentation of my number in 8 bits so that if I have:

int x = 60;
cout << std::hex << x; 

it prints 0x3C ?

Answer 1

try this :

#include<iostream>
#include <iomanip>
using namespace std;

}
int main(){
    int x = 60;
    cout<<showbase; // show the 0x prefix
    cout<<hex<<x; 
    return 0;
}

output :

0x3c