[英]Array in autocomplete not showing anything
Here is my code for jQuery autocomplete: 这是我的jQuery自动完成代码:
PHP Code: PHP代码:
$query = "SELECT * FROM users";
$users = db::getRecords($query);
$usernames = Array();
foreach ($users as $user)
{
$username[] = '"'.$user['username'].'"';
}
Array is associative. 数组是关联的。
JS: JS:
$("#username").autocomplete({
source: [<?php echo join(',', $usernames); ?>],
select: function(event, ui) {
}
});
This array $user
is not getting converted into JavaScript array. $user
这个数组未转换为JavaScript数组。 Nothing happens when I type in my username input. 当我输入用户名输入时,没有任何反应。 How to define the source with PHP array?
如何用PHP数组定义源?
I suggest you do it this way if you're in the same page. 如果您在同一页面上,建议您使用这种方式。
In PHP: 在PHP中:
$username = array();
$query = "SELECT * FROM users";
$users = db::getRecords($query);
foreach ($users as $user) {
$username[] = array('id' => $user['id'], 'username' => $user['username'], 'label' => $user['username']);
}
$username = json_encode($username);
Then on JS: 然后在JS上:
$("#username").autocomplete({
source: <?php echo $username; ?>,
select: function(event, ui) {
alert(ui.item.id); // alets that user id
}
});
But it strongly suggest separate the PHP, so that you'll only need to use echo json_encode($data)
in that PHP. 但是它强烈建议将PHP分开,这样您只需要在该PHP中使用
echo json_encode($data)
。
Then use the php path to the source: 'path/to/phpfile.php'
. 然后使用
source: 'path/to/phpfile.php'
的php路径source: 'path/to/phpfile.php'
。
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