在Java 1.4中使用正则表达式

Question

I am trying to write regex to valid a string which should contain "A - Z", "a - z", "0 - 9", "-" , "_", "/" , "." , "%" , and ":"(period) characters only.

I have written code as below:

import org.apache.regexp.RE;

 private static boolean checkInvalidCharacters (String identity){
        RE re = new RE("(\\w%-/:.)");
   if (!re.match (identity)){
           return true;         
       }
       return false;
   }

I am not sure why this does not work?

Apart from letters and digits special characters required are - / . % : _

Answer 1

Your regex should be:

[-\\w/.%:]+

Instead of using org.apache.regexp.RE you can use Java String API to validate:

private static boolean checkInvalidCharacters (String identity) {
   return !identity.matches("[-\\w/.%:]+");
}

Answer 2

这对我有用：

"^[\\w/.%:\\-]+$"