如何创建表达式 <Action> 在.NET中给出了完全合格的类名和方法名？

Question

I need to create an Expression<Action> that represents calling a method on a class.

As input, I have a string that describes the assembly and class name (standard fully-qualified class name) and another string that defines the method to invoke.

The class/method to be invoked are NOT actually available in the code where the Expression has to be created, so I can't just write ()=>MyClass.Invoke(); -- I don't have MyClass 's assembly as a reference.

Answer 1

System.Action act = () =>
{
    var typeName = "";
    var methodName = "";

    var type = System.Type.GetType(typeName);
    var method = type.GetMethod(methodName);

    object[] constructorArgs = null;
    var obj = type.InvokeMember(null,  System.Reflection.BindingFlags.CreateInstance | System.Reflection.BindingFlags.Public | System.Reflection.BindingFlags.Instance, null, null, constructorArgs);

    object [] methodArgs = null;
    method.Invoke(obj, methodArgs);
};
System.Linq.Expressions.Expression<System.Action> exp = () => act();
exp.Compile()();