[英]Fibonacci sequence multiplying
I tried to make the fibonacci sequence with the following code: 我试图用以下代码制作斐波那契数列:
def fibonacci(n): # write Fibonacci series up to n
"""Print a Fibonacci series up to n."""
a = 0
b = 1
the_list = []
while n > len(the_list):
the_list.append(a)
#By saying a = b and b = a+b we define the
#fibonacci sequence, since this is how the
#fibonacci sequence works.
a = b
b = a+b
print the_list
# Now call the function we just defined:
fibonacci(10)
As far as I know this code should do it but instead of giving me the fibonacci sequence its giving the following output: 据我所知,该代码应该执行此操作,但与其给我斐波那契序列,不如给出以下输出:
[0, 1, 2, 4, 8, 16, 32, 64, 128, 256]
So my fibonacci sequence is multiplying instead of working correcly. 所以我的斐波那契数列是乘法而不是正确地工作。 I have no idea why because i thought
我不知道为什么,因为我想
a = b
b = a+b
should do the trick, if i look at my while loop the statements for this loop are also correct, so I just dont get it why i dont get the right output. 应该可以解决问题,如果我看看我的while循环,这个循环的语句也是正确的,所以我只是不明白为什么我没有得到正确的输出。
So if someone could explain me why this code is not working it would be highly appriciated 因此,如果有人可以向我解释为什么此代码无法正常工作,那么它会受到高度重视。
Your code is creating an exponential sequence because of a logic flaw. 由于逻辑缺陷,您的代码正在创建指数序列。 Based on your code:
根据您的代码:
Start:
a = 0
b = 1
1st iteration:
a = b = 1
b = a + 1 = 1 + 1 = 2
2nd iteration:
a = b = 2
b = a + 2 = 2 + 2 = 4
As you can see the fact that you set a
before performing the b
calculation causes your issue. 如您所见,在执行
b
计算之前设置a
会导致问题。
Instead you need would something like (to prove the point): 相反,您需要以下内容(证明这一点):
tmp = a
a = b
b = tmp + a
A little extra math would eliminate the need for the extra variable: 进行一些额外的数学运算将消除对额外变量的需要:
b += a
a = b - a
But the easiest (and most pythonic) way would be: 但是最简单(也是最pythonic)的方式是:
a, b = b, a + b
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