Spring Hibernate - 无法为当前线程获取事务同步会话

Question

I created an application with spring + hibernate, but I always get this error. This is my first application with hibernate, I read some guides but I can not solve this problem. Where am I doing wrong?

This is the code of my application

ott 05, 2014 4:03:06 PM org.springframework.context.support.ClassPathXmlApplicationContext prepareRefresh
Informazioni: Refreshing   org.springframework.context.support.ClassPathXmlApplicationContext@1eab16b: startup date  [Sun Oct 05 16:03:06 CEST 2014]; root of context hierarchy
ott 05, 2014 4:03:06 PM org.springframework.beans.factory.xml.XmlBeanDefinitionReader loadBeanDefinitions
Informazioni: Loading XML bean definitions from class path resource [springConfig.xml]
ott 05, 2014 4:03:08 PM org.hibernate.annotations.common.reflection.java.JavaReflectionManager <clinit>
INFO: HCANN000001: Hibernate Commons Annotations {4.0.5.Final}
ott 05, 2014 4:03:08 PM org.hibernate.Version logVersion
INFO: HHH000412: Hibernate Core {4.3.6.Final}
ott 05, 2014 4:03:08 PM org.hibernate.cfg.Environment <clinit>
INFO: HHH000206: hibernate.properties not found
ott 05, 2014 4:03:08 PM org.hibernate.cfg.Environment buildBytecodeProvider
INFO: HHH000021: Bytecode provider name : javassist
ott 05, 2014 4:03:09 PM org.hibernate.dialect.Dialect <init>
INFO: HHH000400: Using dialect: org.hibernate.dialect.MySQL5Dialect
ott 05, 2014 4:03:09 PM org.hibernate.engine.transaction.internal.TransactionFactoryInitiator initiateService
INFO: HHH000399: Using default transaction strategy (direct JDBC transactions)
ott 05, 2014 4:03:09 PM org.hibernate.hql.internal.ast.ASTQueryTranslatorFactory <init>
INFO: HHH000397: Using ASTQueryTranslatorFactory
Exception in thread "main" org.hibernate.HibernateException: Could not obtain transaction-synchronized Session for current thread
at org.springframework.orm.hibernate4.SpringSessionContext.currentSession(SpringSessionContext.java:134)
at org.hibernate.internal.SessionFactoryImpl.getCurrentSession(SessionFactoryImpl.java:1014)
at coreservlets.StudentDAOImpl.create(StudentDAOImpl.java:19)
at coreservlets.MainApp.main(MainApp.java:14)

student.java

package coreservlets;

public class Student {

    private Integer id;
    private String name;
    private Integer age;

    public Integer getId(){return id;}//getId

    public void setId(Integer id){this.id=id;}//setId

    public String getName(){return name;}//getName

    public void setName(String name){this.name=name;}//setName

    public Integer getAge(){return age;}//getAge

    public void setAge(Integer age){this.age=age;}//setAge

}//Student

studentDAO.java

package coreservlets;

import org.hibernate.SessionFactory;

public interface StudentDAO {

    public void setSessionFactory(SessionFactory sessionFactory);

    public void create(String name,Integer age);

}//StudentDAO

StudentDAOImpl.java

package coreservlets;

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Repository;

@Repository
public class StudentDAOImpl implements StudentDAO {

    private SessionFactory sessionFactory;

    @Autowired
    public void setSessionFactory(SessionFactory sessionFactory){
        this.sessionFactory=sessionFactory;
    }//setSessionFactory

    public void create(String name,Integer age){
        Session session=sessionFactory.getCurrentSession();
        Student student=new Student();
        student.setName(name);
        student.setAge(age);
        session.save(student);
    }//create

}//StudentDAOImpl

MainApp.java

package coreservlets;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class MainApp {

    public static void main(String[] args) {

        ApplicationContext context=new ClassPathXmlApplicationContext("springConfig.xml");

        StudentDAOImpl student=(StudentDAOImpl) context.getBean("studentDAOImpl");

        student.create("Alessandro", new Integer(33));


    }//main

}//MainApp

springConfig.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.1.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.1.xsd
    http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.1.xsd">

<context:annotation-config/>

<context:component-scan base-package="coreservlets"/>

<bean id="dataSource" class="org.apache.commons.dbcp2.BasicDataSource">
  <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
  <property name="url" value="jdbc:mysql://localhost:3306/spring_hibernate"/>
  <property name="username" value="root"/>
  <property name="password" value="password"/>
  <property name="initialSize" value="5"/>
  <property name="maxTotal" value="10"/>
</bean>

<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="hibernateProperties">
    <value>
            hibernate.dialect=org.hibernate.dialect.MySQLDialect
    </value>
</property>

</bean>

</beans>

sql

create table student
(
id integer not null auto_increment,
name varchar(20) not null,
age integer not null,
primary key(id)
);

Answer 1

You must enable the transaction support ( <tx:annotation-driven> or @EnableTransactionManagement ) and declare the transactionManager and it should work through the SessionFactory .

You must add @Transactional into your @Repository

With @Transactional in your @Repository Spring is able to apply transactional support into your repository.

Your Student class has no the @javax.persistence.* annotations how @Entity , I am assuming the Mapping Configuration for that class has been defined through XML.

Answer 2

I have had the same issue, but in a class that was not a part of the service layer. In my case, the transaction manager was simply obtained from the context by the getBean() method, and the class belonged to the view layer - my project utilizes OpenSessionInView technique.

The sessionFactory.getCurrentSession() method, has been causing the same exception as the author's. The solution for me was rather simple.

Session session;

try {
    session = sessionFactory.getCurrentSession();
} catch (HibernateException e) {
    session = sessionFactory.openSession();
}

If the getCurrentSession() method fails, the openSession() should do the trick.

Answer 3

在类服务中添加spring的注解@Transactional

Answer 4

In your xyz.DAOImpl.java

Do the following steps:

//Step-1: Set session factory

@Resource(name="sessionFactory")
private SessionFactory sessionFactory;

public void setSessionFactory(SessionFactory sf)
{
    this.sessionFactory = sf;
}

---

//Step-2: Try to get the current session, and catch the HibernateException exception.

---

//Step-3: If there are any HibernateException exception, then true to get openSession.

try 
{
    //Step-2: Implementation
    session = sessionFactory.getCurrentSession();
} 
catch (HibernateException e) 
{
    //Step-3: Implementation
    session = sessionFactory.openSession();
}

Answer 5

I added these configuration in web.xml and it works well for me!

<filter>
    <filter-name>OpenSessionInViewFilter</filter-name>
    <filter-class>org.springframework.orm.hibernate5.support.OpenSessionInViewFilter</filter-class>
    <init-param>
        <param-name>sessionFactoryBeanName</param-name>
        <param-value>sessionFactory</param-value>
    </init-param>
    <init-param>
        <param-name>flushMode</param-name>
        <param-value>AUTO</param-value>
    </init-param>
</filter>
<filter-mapping>
    <filter-name>OpenSessionInViewFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

Additionally, the most ranked answer give me clues to prevent application from panic at the first run.

Answer 6

You need to allow transaction to your DAO method. Add,

@Transactional(readOnly = true, propagation=Propagation.NOT_SUPPORTED)

over your dao methods. And @Transactional should be from the package:

org.springframework.transaction.annotation.Transactional

Answer 7

@Transactional =javax.transaction.Transactional . Put it just beside @Repository .

Answer 8

I had this error too because in the file where I used @Transactional annotation, I was importing the wrong class

import javax.transaction.Transactional; 

Instead of javax, use

import org.springframework.transaction.annotation.Transactional; 

Answer 9

My solution was (using Spring) putting the method that fails inside another method that creates and commits the transaction.

To do that I first injected the following:

@Autowired
private PlatformTransactionManager transactionManager;

And finally did this:

public void newMethod() {
    DefaultTransactionDefinition definition = new DefaultTransactionDefinition();
    TransactionStatus transaction = transactionManager.getTransaction(definition);

    oldMethod();

    transactionManager.commit(transaction);
}

Answer 10

I encountered the same problem and finally found out that the <tx:annotaion-driven /> was not defined within the [dispatcher]-servlet.xml where component-scan element enabled @service annotated class.

Simply put <tx:annotaion-driven /> with component-scan element together, the problem disappeared.

Answer 11

My similar issue got fixed with below 2 approaches.

1) Through manually handling transactions:

Session session = sessionFactory.getCurrentSession();
Transaction tx = session.beginTransaction();
UserInfo user = (UserInfo) session.get(UserInfo.class, 1);
tx.commit();

2) Tell Spring to open and manage transactions for you in your web.xml filters and Ensure to use @Repository @Transactional :

<filter>
  <filter-name>hibernateFilter</filter-name>
  <filter-class>org.springframework.orm.hibernate5.support.OpenSessionInViewFilter</filter-class>
  <init-param>
    <param-name>sessionFactory</param-name>
    <param-value>session.factory</param-value>
  </init-param>
</filter>
<filter-mapping>
  <filter-name>hibernateFilter</filter-name>
  <url-pattern>/*</url-pattern>
</filter-mapping>

Answer 12

My configuration was like this. I had a QuartzJob , a Service Bean , and Dao . as usual it was configured with LocalSessionFactoryBean (for hibernate) , and SchedulerFactoryBean for Quartz framework. while writing the Quartz job , I by mistake annotated it with @ Service , I should not have done that because I was using another strategy to wire the QuartzBean using AutowiringSpringBeanJobFactory extending SpringBeanJobFactory .

So what actually was happening is that due to Quartz Autowire , TX was getting injected to the Job Bean and at the same time Tx Context was set by virtue of @ Service annotation and hence the TX was falling out of sync !!

I hope it help to those for whom above solutions really didn't solved the issue. I was using Spring 4.2.5 and Hibernate 4.0.1 ,

I see that in this thread there is a unnecessary suggestion to add @ Transactional annotation to the DAO(@ Repository ) , that is a useless suggestion cause @ Repository has all what it needs to have don't have to specially set that @ transactional on DAOs , as the DAOs are called from the services which have already being injected by @Trasancational . I hope this might be helpful people who are using Quartz , Spring and Hibernate together.

Answer 13

将transaction-manager添加到spring-servlet.xml 中的<annotation-driven/> ：

<tx:annotation-driven transaction-manager="yourTransactionBeanID"/>

Answer 14

Check your dao class. It must be like this:

Session session = getCurrentSession();
Query query = session.createQuery(GET_ALL);

And annotations:

@Transactional
@Repository

Answer 15

In this class above @Repository just placed one more annotation @Transactional it will work. If it works reply back( Y / N ):

@Repository
@Transactional
public class StudentDAOImpl implements StudentDAO

Answer 16

Thanks for comment of mannedear. I use springmvc and in my case I have to use as

@Repository
@Transactional
@EnableTransactionManagement
public class UserDao {
...
}

and I also add spring-context to pom.xml and it works

Answer 17

I had the same issue. I resolved it doing the following:

1. Add the this line to the dispatcher-servlet file:

    <tx:annotation-driven/>

   Check above <beans> section in the same file. These two lines must be present:

    xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation= "http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd"

2. Also make sure you added @Repository and @Transactional where you are using sessionFactory .

    @Repository @Transactional public class ItemDaoImpl implements ItemDao { @Autowired private SessionFactory sessionFactory;

Answer 18

My Database table has mismatch column name with the Java Object (@Entity) which leads to throw the above exception.

By updating the table with appropriate column name resolves this issue.

Answer 19

In my case the problem was a Controller trying to access directly to a DAO with @Repository. Adding an @Service layer on top of the @Repository fixed the problem