将目录中的文件存储到数组中，然后遍历该数组

Question

I have a folder called 'sql' that contains .sql files. I want to write a script that searches for all .sql files, puts the filename into an array, and then kicks off each file.

ie:

 #!/bin/bash

 # Options
 DBHOST=MySQL-hostname
 DBNAME=MySQL-database
 DBUSER=MySQL-username
 DBPASS=MySQL-password

 # Find .sql Files
 ???

 # Create MySQL Tables
 for i in "${TBNAME[@]}"; do
   mysql -h "$DBHOST" -u "$DBUSER" -p"$DBPASS" "$DBNAME" < $TBNAME[$i]
 done

How can I search for .sql files within a specified folder?

Answer 1

for sqlfile in sql/*.sql ; do
    # do things to $sqlfile
done

For example you can save the full pathnames in a table by using echo "$PWD/$sqlfile"

Answer 2

Late aswer (after accepted one) but for the record:

printf "source %s\n" sql/**/*.sql | mysql --batch

for this you need to have in the ~/.bash_profile line:

shopt -s globstar #or put this before the above line

How it works:

printf "source %s\n" sql/**/*.sql 

produces lines like

source sql/some/file.sql
source sql/other/file2.sql
#and such...

recursively for all found *.sql files, and the

mysql --batch .... other arguments

will read the "source filename" lines - and executes the sql commands in the files, all in one execution, not need start (run) multiple times the mysql command...