[英]char array to int in c++
I am unable to get the part of the string stored in form of char array. 我无法获取以char数组形式存储的字符串部分。
char code1 [12]={0};
char c;
string compressed_file;
I am taking the input from a text file, till a ',' occurs in it. 我正在从文本文件中获取输入,直到其中出现“,”。
cout<<"Input compressed_file name"<<endl;
cin>>compressed_file;
string extracted_file;
cout<<"Input extracted_file name"<<endl;
cin>>extracted_file;
ifstream input;
input.open(compressed_file.c_str());
ofstream decompresscode;
decompresscode.open(extracted_file.c_str());
input>>c;
while(c != ',')
{
int i=0;
code1[i]=c;
cout<<code1[i];
i++;
input>>c;
}
int old=atoi(code1);
cout<<old;
After printing the value of code1 here, I am only getting the first letter of the array. 在这里打印code1的值后,我只得到数组的第一个字母。 My
code1
is 66 , it is printing only 6 . 我的
code1
是66 ,它只打印6 。
You are always saving in the position 0
: 您始终保存在位置
0
:
int i=0; // this need to be out of while loop
code1[i]=c;
cout<<code1[i];
You need also to add a check for read at max 12 char (to not overflow code1
). 您还需要添加最多12个字符的读取检查(不溢出
code1
)。 The code could be something like. 代码可能像这样。
input >> c;
int i = 0;
while (c != ',' && i < sizeof(code1)) {
code1[i] = c;
cout << code1[i];
i++;
input >> c;
}
Move int i = 0
outside the loop . 将
int i = 0
移到循环外 。 As it is, you are resetting it to 0
each time. 照原样,您每次都将其重置为
0
。
input>>c;
int i=0; //move to here
while(c != ',')
{
code1[i]=c;
cout<<code1[i];
i++;
input>>c;
}
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