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在具有相同ID的选择查询中合并两行

[英]Combine two rows in select query having same id's

I have this query 我有这个查询

SELECT 
`sys_forms`.`FormID`,
`sys_forms`.`FormName`,
`sys_forms`.`FormCIPath`,
`sys_forms_in_groups`.`IsMenuLink`,
`sys_forms_in_groups`.`GroupID`

FROM (`sys_forms`) INNER JOIN `sys_forms_in_groups` 
ON `sys_forms_in_groups`.`FormID` = `sys_forms`.`FormID` WHERE `GroupID` = 1
UNION
SELECT 
`sys_forms`.`FormID`,
`sys_forms`.`FormName`,
`sys_forms`.`FormCIPath`,
`sys_forms_in_groups`.`IsMenuLink`,
`sys_forms_in_groups`.`GroupID`

FROM (`sys_forms`) INNER JOIN `sys_forms_in_groups` 
ON `sys_forms_in_groups`.`FormID` = `sys_forms`.`FormID` WHERE `GroupID` = 2

it is returning me this below data. 它返回我下面的数据。

在此处输入图片说明

As you can see, there are two identical FormID . 如您所见,有两个相同的FormID

What i want that if the id's are same then rows should be merged but GroupID is different for both identical FormID's. 我想要的是,如果id相同,则应合并行,但对于相同的FormID, GroupID不同。

So i want them to join in CSV format so that the result would be 所以我希望他们以CSV格式加入,这样结果是

FormID FormName        -  -   GroupID
-------------------------------------------------
48     FormsIn Groups  -  -    1,2          

Your first query can just be written as: 您的第一个查询可以写成:

SELECT sf.`FormID`, sf.`FormName`, sf.`FormCIPath`, sfig.`IsMenuLink`, sfig.`GroupID`
FROM `sys_forms` sf INNER JOIN
     `sys_forms_in_groups` sfig
     ON sfig.`FormID` = sf.`FormID`
WHERE `GroupID` IN (1, 2);

Note the use of table aliases and the single where clause with in . 注意使用表别名和in的单个where子句。

To get what you want, use group by and include only the columns you want: 要获得所需的内容,请使用group by并仅包含所需的列:

SELECT sf.`FormID`, sf.`FormName`, 
       group_concat(sfig.`GroupID`) as groupids
FROM `sys_forms` sf INNER JOIN
     `sys_forms_in_groups` sfig
     ON sfig.`FormID` = sf.`FormID`
WHERE `GroupID` IN (1, 2)
GROUP BY sf.`FormID`, sf.`FormName`, sf.`FormCIPath`, sfig.`IsMenuLink`;

The specified result can be returned with a query like this: 指定的结果可以通过如下查询返回:

SELECT f.FormID
     , f.FormName
     , f.FormCIPath
     , MAX(g.IsMenuLink) AS IsMenuLink
     , GROUP_CONCAT(DISTINCT g.GroupID ORDER BY g.GroupID) AS GroupIDs
  FROM `sys_forms` f 
  JOIN `sys_forms_in_groups` g
    ON g.FormID = f.FormID
   AND g.GroupID IN (1,2)
 GROUP BY f.formID

The GROUP_CONCAT aggregate will combine multiple values into a comma separated list. GROUP_CONCAT聚合将多个值组合成一个逗号分隔的列表。 (A different delimiter can be specified, the default is a comma.) (可以指定其他定界符,默认为逗号。)

We use the MAX aggregate around the IsMenuLink column so we get a non-NULL value in place of NULL. 我们在IsMenuLink列周围使用MAX聚合,因此我们获得了一个非NULL值代替NULL。

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