MySQL查询高级搜索的多个条件

Question

I'm working through an advanced search query where users select checkboxes based on multiple criteria. I'm a beginner so I'm hoping I can find out if I'm on the right track. I'm aware the query is quite the mess.

Edit: I realized this needed to be two questions, so I've revised to be strictly a query question

Table data

Table ss_users
user_id  first_name   last_name   admin_level   user_approved  
1        nick         jones       0             1      
2        johnny       rocket      0             1      

Table ss_user_profile_status
user_id  photo_uploaded   
1        1
2        1

Table ss_user_photos
photo_id  user_id  filename      selected
1         1        photo_1.jpg   1
2         2        photo_2.jpg   0
3         2        photo_2.jpg   1

Table ss_general
user_id  city        state      zip     neighborhood
1        baltimore   maryland   00125   hamsterdam
2        lakeland    maine      11542   treemont

Table ss_languages
user_id  french  german  italian  spanish
1        0       1       0        1
2        0       0       1        1

Table ss_experience
user_id  waldorf  kumon  homeschooling 
1        0       1       0
2        0       0       1

My current results are all users, which should not be the case:

SELECT 
    ss_users.*, ss_user_profile_status.*, ss_user_photos.*, ss_general.*, 
    ss_languages.*, ss_experience.*, ss_users.user_id AS userID, 
    ss_user_profile_status.user_id, ss_languages.user_id AS langID
FROM 
    ss_users
JOIN 
    ss_user_profile_status ON ss_users.user_id = ss_user_profile_status.user_id
LEFT JOIN 
    ss_user_photos ON ss_users.user_id = ss_user_photos.user_id
AND 
    ss_user_photos.selected = 1
LEFT JOIN 
    ss_languages ON ss_users.user_id = ss_languages.user_id
LEFT JOIN 
    ss_general ON ss_users.user_id = ss_general.user_id
LEFT JOIN 
    ss_experience ON ss_users.user_id = ss_experience.user_id
WHERE 
    ss_users.user_id = ss_user_profile_status.user_id 
AND 
    ss_general.neighborhood_select LIKE '%hamsterdam%'
OR 
    ss_languages.spanish = 1
OR 
    ss_experience.kumon = 1
AND 
    ss_users.sitter_approved = 1
AND 
    ss_users.admin_level = 0
GROUP BY 
    ss_users.user_id DESC

For the output I need to represent much of the users profile, that's why I'm selecting a lot of table data, as well as the extra joins.

Answer 1

For your big fat SQL selection

SELECT 
    ss_users.*, ss_user_profile_status.*, ss_user_photos.*, ss_general.*, 
    ss_languages.*, ss_experience.*, ss_users.user_id AS userID, 
    ss_user_profile_status.user_id, ss_languages.user_id AS langID
FROM ss_users
    JOIN ss_user_profile_status ON ss_users.user_id = ss_user_profile_status.user_id
    LEFT JOIN ss_user_photos ON ss_users.user_id = ss_user_photos.user_id AND ss_user_photos.selected = 1
    LEFT JOIN ss_languages ON ss_users.user_id = ss_languages.user_id
    LEFT JOIN ss_general ON ss_users.user_id = ss_general.user_id
    LEFT JOIN ss_experience ON ss_users.user_id = ss_experience.user_id
WHERE 
    ( ss_general.neighborhood_select LIKE '%hamsterdam%' OR ss_languages.spanish = 1 OR ss_experience.kumon = 1 ) AND ss_users.sitter_approved = 1 AND ss_users.admin_level = 0

I only edit few places like adding bracket around the OR and remove the first condition cause it seems redundant, and also remove the group by since it will left some data out