[英]Create dynamic table with api data
How do I make my table dynamically list all the values it pulls from the api, atm it only pulls 1 record and puts it in the table, the rest of the data gets put outside it 我如何使我的表动态列出从api中提取的所有值,atm它仅提取1条记录并将其放入表中,其余数据置于其外部
Probably something very small I'm missing here, but can't put my finger on it 我可能在这里想念的东西很小,但不能把手指放在上面
Thanks for any help, very appreciated. 感谢您的帮助,非常感谢。
<?php
$trackingId = $_POST['trackingId'];
if (isset($_POST['trackingId'])) {
$fetch = json_decode(file_get_contents(sprintf('apigoeshere', $trackingId)));
if ($fetch->status != 'OK') {
echo sprintf('Error: %s', $fetch->message);
} else {
//example how to access statistics variable
$inactiveAccounts = $fetch->statistics->inactiveAccounts;
echo sprintf('Inactive accounts: %d' . "<br /><br />", $inactiveAccounts);
?>
<table border="1">
<tr>
<th>Account name</th>
<th>Level</th>
</tr>
<?php
//example how to display all accounts username
foreach ($fetch->accounts as $account) {
?>
<tr>
<td><?php
echo $account->username;
?></td>
<td><?php
echo $account->currentLevel;
?></td>
</tr>
</table>
<?php
}
}
}
?>
Didnt close foreach in right place. 没有在正确的位置关闭foreach。 use this code instead 使用此代码
<?php
$trackingId = $_POST['trackingId'];
if (isset($_POST['trackingId'])) {
$fetch = json_decode(file_get_contents(sprintf('apigoeshere', $trackingId)));
if ($fetch->status != 'OK') {
echo sprintf('Error: %s', $fetch->message);
} else {
//example how to access statistics variable
$inactiveAccounts = $fetch->statistics->inactiveAccounts;
echo sprintf('Inactive accounts: %d' . "<br /><br />", $inactiveAccounts);
?>
<table border="1">
<tr>
<th>Account name</th>
<th>Level</th>
</tr>
<?php
//example how to display all accounts username
foreach ($fetch->accounts as $account) {
?>
<tr>
<td><?php
echo $account->username;
?></td>
<td><?php
echo $account->currentLevel;
?></td>
</tr>
<?php
}
?>
</table>
<?php
}
}
?>
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