如何在xslt中覆盖xml值？

Question

I want to transform xml to another xml with few conditions. One of condition is whenever my xml element has DC19DAKHN or DC19D0000 , in transformed xml I would like to override them with value MN019015J .

How do I do this in XSLT?

My XML Code

<MyID>DC19DAKHN</MyID>

My xslt output is

<myID>DC19D0000</myID>

I want this to look like this instead

<myID>MN019015J</myID>

Do I use If Choose?

Answer 1

Try this:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="node()|@*">
    <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="MyID/text()[.='DC19DAKHN']">MN019015J</xsl:template>

<xsl:template match="myID/text()[.='DC19D0000']">MN019015J</xsl:template>

</xsl:stylesheet>