Python-正则表达式查找字符串中的所有匹配项并替换

Question

I have a problem on replacing string using regex, seem I can't get it to work

string = "<font x=''>test</font> <font y=''>test2</font> <font z=''>test3</font>"
if re.search("(<font .*?>)", string, re.IGNORECASE):
    r = re.compile(r"<font (?P<name>.*?)>.*?</font>", re.IGNORECASE)
    string = r.sub(r'', string)

For some reason all the regex deletes the entire string '' . It should return as test test2 test3

Answer 1

Here it is,

>>> import re
>>> string = "<font x=''>test</font> <font y=''>test2</font> <font z=''>test3</font>"
>>> if re.search("(<font .*?>)", string, re.IGNORECASE):
...     r = re.compile(r"</?font.*?>", re.IGNORECASE)
...     string = r.sub(r'', string)
... 
>>> string
'test test2 test3'

DEMO

Pattern Explanation:

• </?font.*?> This regex would match all the opening and closing font tags. By adding ? after the / will make the previous character that is / as optional.
• .*? Will do a shortest possible match. ? after the * would force the regex engine to do a shortest possible match because * is greedy by default. It could consume so many chars as much as possible.
• > Matches the > symbol literally.
• re.IGNORECASE is called case-insensitive modifier.

Answer 2

>([^<]*)<\/

you can use it as

y="<font x=''>test</font> <font y=''>test2</font> <font z=''>test3</font>"
x=re.findall(r"(?<=>)([^<]*)(?=<\/)",y) 
str=" ".join(x)
print str

See demo

http://regex101.com/r/xT7yD8/6