[英]ServerEndpoint and web.xml
I have some Soap, REST servlets and now one WebSocket: 我有一些Soap,REST servlet和一个WebSocket:
@ServerEndpoint("/game")
public class WebSocketgame{
...
}
I have next trouble: WebSocket dont visible, if web.xml is exists. 我遇到下一个麻烦:如果存在web.xml,则WebSocket不可见。 In web.xml describes jdbc resources,servlets ant other... When i'm delete web.xml - websocket successfully visible.
在web.xml中描述了jdbc资源,servlet和其他...当我删除web.xml时-websocket成功可见。 How can I fix this problem?
我该如何解决这个问题?
Update web.xml: 更新web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
<listener>
<listener-class>com.sun.xml.ws.transport.http.servlet.WSServletContextListener</listener-class>
</listener>
<servlet>
<servlet-name>ConfigServlet</servlet-name>
<servlet-class>com.example.ConfigServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>MainService</servlet-name>
<servlet-class>com.sun.xml.ws.transport.http.servlet.WSServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>ConfigServlet</servlet-name>
<url-pattern>/ConfigServlet</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>JsonServlet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.example.json</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>JsonServlet</servlet-name>
<url-pattern>/json/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>propfile</param-name>
<param-value>/WEB-INF/server_config.txt</param-value>
</context-param>
<servlet-mapping>
<servlet-name>MainService</servlet-name>
<url-pattern>/MainService</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<resource-ref>
<description>postgreSQL Datasource example</description>
<res-ref-name>jdbc/postgres</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>
</web-app>
Try adding 尝试添加
<beans xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/beans_1_1.xsd"
bean-discovery-mode="annotated">
in beans.xml file 在beans.xml文件中
I believe you need to add servlet configuration for those with something like this 我相信您需要为具有此类内容的人添加servlet配置
<servlet>
<servlet-name>gameServer</servlet-name>
<servlet-class>WebSocketgame.SocketEndPoint</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>gameServer</servlet-name>
<url-pattern>/game</url-pattern>
</servlet-mapping>
I think you should configure your main servlet (MainService) to serve all urls /*
or /MainService/*
and than use websocket as /MainService/game
. 我认为您应该配置主servlet(MainService)以提供所有URL
/*
或/MainService/*
而不是将websocket用作/MainService/game
。
Your class 你的班
@ServerEndpoint("/MainService/game")
public class WebSocketgame{
...
}
And web.xml http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"> com.sun.xml.ws.transport.http.servlet.WSServletContextListener ConfigServlet com.example.ConfigServlet 1 MainService com.sun.xml.ws.transport.http.servlet.WSServlet 1 和web.xml http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd“> com.sun.xml.ws.transport.http.servlet.WSServletContextListener ConfigServlet com.example.ConfigServlet 1 MainService com.sun.xml.ws.transport.http.servlet.WSServlet 1
<servlet-mapping>
<servlet-name>ConfigServlet</servlet-name>
<url-pattern>/ConfigServlet</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>JsonServlet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.example.json</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>JsonServlet</servlet-name>
<url-pattern>/json/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>propfile</param-name>
<param-value>/WEB-INF/server_config.txt</param-value>
</context-param>
<servlet-mapping>
<servlet-name>MainService</servlet-name>
<url-pattern>/MainService/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<resource-ref>
<description>postgreSQL Datasource example</description>
<res-ref-name>jdbc/postgres</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Container</res-auth>
</resource-ref>
And make your js (or other websocket client) to connect to /MainService/game instead of /game 并使您的js(或其他websocket客户端)连接到/ MainService / game而不是/ game
I had the same problem. 我有同样的问题。 My solution was extend the endpoint class to HttpServlet.
我的解决方案是将终结点类扩展到HttpServlet。
@ServerEndpoint("/game")
public class WebSocketgame extends HttpServlet {
...
}
And for web.xml definition 并为web.xml定义
<servlet>
<display-name>Webgame</display-name>
<servlet-name>Webgame</servlet-name>
<servlet-class>com.example.WebSocketgame</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
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