当从键盘输入 10 个数字时，打印 while 循环中的最大数字

Question

Every time my output prints out the last number given through the Scanner as the largest number. This program needs to be modified in a way, that it scans through the numbers I input and prints out the largest number.

PS this is not school work, its just coding in my spare time.

import java.util.Scanner;

public class FindTheLargestNumber {

    public static void main(String[] args) {

        int counter = 1;
        int number;
        int largest = 0;

        Scanner input = new Scanner(System.in);

        System.out.println("Enter the number: ");
        number = input.nextInt();

        while(counter < 10)
        {
            System.out.println("Enter the number: ");
            number = input.nextInt();

            counter++;

        }


        if(number > 1)
            largest = number;


        System.out.println("the largest number is " + largest);
    }
}

CONSOLE:

Enter the number: 
123

Enter the number: 
443

Enter the number: 
221

Enter the number: 
453

Enter the number: 
553

Enter the number: 
665

Enter the number: 
776

Enter the number: 
23

Enter the number: 
12

Enter the number: 
23


output: 
the largest number is 23

it should clearly print out 776, but it prints the last number I input as the largest.

Answer 1

You are checking just for the last accepted number if it is greater than 1 you are assigning it to the largest. But you have to make sure that you check for all the numbers and compare them to have the largest among them.

This code will work for you

import java.util.Scanner;
public class test {
    public static void main(String[] args) {

        int counter = 1;
        int number;
        int largest = 0;

        Scanner input = new Scanner(System.in);

        System.out.println("Enter the number: ");
        number = input.nextInt();

        while(counter < 10)
        {
            System.out.println("Enter the number: ");
            number = input.nextInt();

            if(largest < number) {
                largest = number;
            }

            counter++;

        }

        System.out.println("the largest number is " + largest);
    }
}

Answer 2

Here you are checking the condition outside the loop it only checks for the last input. As you are accepting first value before the loop you should set that value as largest before the loop. (Pointed out by khelwood )

So it should be like this,

System.out.println("Enter the number: ");
number = input.nextInt();
largest=number;
while(counter < 10){
    System.out.println("Enter the number: ");
    number = input.nextInt();        
    if(number > largest)//If largest is small, set current number as largest
        largest = number;
    counter++;
}

Answer 3

You should move this within the while loop:

if(number > largest)
    largest = number;

Answer 4

    int counter = 1;
    int number;
    int largest = 0;
    Scanner scanner = new Scanner(System.in);
    for (;counter <= 10; counter++) {
        System.out.println("ENTER " + counter + " NUMBER");
        number = scanner.nextInt();


        if (number > largest  ) {
            largest = number;

        }

    }
    System.out.println("THE LARGEST NUMBER FOUND SO FAR IS: " + largest);