[英]How to replace last 15 digits of a string with x?
Let's say I've got a string which I want to display on my user's settings page. 假设我有一个要显示在用户设置页面上的字符串。 It's the HWID of the specific user but I want to hide like the last 15 characters from the string with
x
for example. 这是特定用户的HWID,但我想隐藏像与字符串中的最后15个字符
x
的例子。 How to do this ? 这个怎么做 ? Probably
preg_replace()
.. please let me know. 大概
preg_replace()
..请让我知道。
Example string: aaaec315bbfb9184fd9d7c8e165b297d
but it will display like aaaec315bbfb9184f**************
for exmaple 示例字符串:
aaaec315bbfb9184fd9d7c8e165b297d
但示例显示为aaaec315bbfb9184f**************
I believe it can only contain an alphanumeric characters since it's a HWID. 我相信它只能包含字母数字字符,因为它是HWID。
$string = substr($string,0,-15)."xxxxxxxxxxxxxxx";
While @hellocde's example does do this, I would just use the native substr_replace function instead as this is what it's intended for. 虽然@hellocde的示例做到了这一点,但我只是使用了本机的substr_replace函数,因为这正是它的目的。
substr_replace($string, 'xxxxxxxxxxxxxx', -15);
Which will produce: 会产生:
aaaec315bbfb9184fdxxxxxxxxxxxxxx
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