快速获取 UIViewController 的类名

Question

How do you get the class name of a UIViewController class in Swift?

In Objective-C, we can do something like this:

self.appDelegate = (shAppDelegate *)[[UIApplication sharedApplication] delegate];
    UIViewController *last_screen = self.appDelegate.popScreens.lastObject ;
    
    if(last_screen.class != self.navigationController.visibleViewController.class){

    //.......
}

but in Swift I tried:

let appDelegate = UIApplication.sharedApplication().delegate as AppDelegate
    let last_screen = appDelegate.popScreens?.lastObject as UIViewController

Can't do this.

if last_screen.class != self.navigationController.visibleViewController.class {

//....

}

no class method of UIViewController ie last screen

Answer 1

要知道您的班级名称，您可以这样称呼：

var className = NSStringFromClass(yourClass.classForCoder)

Answer 2

不需要知道您的班级名称的最干净的方法是这样的。

let name = String(describing: type(of: self))

Answer 3

A simple way in swift 3 is to write the below code:

for instances:

let className = String(describing: self)

for classes:

let className = String(describing: YourViewController.self)

Answer 4

Expanding on juangdelvalle's answer .

I added this as an extension so that it's reusable and easier to call from any view controller. Also in some cases NSStringFromClass in Swift returns a string in the format like this:

< project name >.viewControllerClassName .

This extension property is modified to get rid of the project name prefix and return only the class name.

extension UIViewController {
    var className: String {
        NSStringFromClass(self.classForCoder).components(separatedBy: ".").last!
    }
}

Answer 5

Swift 4

Suppose we have class with name HomeViewController . Then you can get name of class with the following code:

let class_name = "\(HomeViewController.classForCoder())"

The classForCoder() method returns AnyClass object (name of your class) which we convert to string for user.

Answer 6

Here is a swift3 version of isuru's answer.

extension UIViewController {
    var className: String {
        return NSStringFromClass(self.classForCoder).components(separatedBy: ".").last!;
    }
}

Answer 7

Swift 5 solution:

extension NSObject {
  var className: String {
    return String(describing: type(of: self))
  }

  class var className: String {
    return String(describing: self)
  }
}

USAGE:

class TextFieldCell: UITableVIewCell {
}

class LoginViewController: UIViewController {
  let cellClassName = TextFieldCell.className
}

Answer 8

该属性在 Swift 中称为dynamicType 。

Answer 9

Use String.init(describing: self.classForCoder)

example:

let viewControllerName = String.init(describing: self.classForCoder)
print("ViewController Name: \(viewControllerName)")

Answer 10

How about:

    extension NSObject {

    static var stringFromType: String? {
        return NSStringFromClass(self).components(separatedBy: ".").last
    }

    var stringFromInstance: String? {
        return NSStringFromClass(type(of: self)).components(separatedBy: ".").last
    }
}

Answer 11

我们也可以这样做： Swift 5.1 中的String(describing: Self.self) 。