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结构指针中的字符串数组

[英]Array of string in a struct pointer

I have a following struct: 我有以下结构:

strcut records
{
    char **lines;
    int count;
}

There is a function get_pwent() which the concerning code is like this: 有一个函数get_pwent() ,相关代码如下:

struct records *passwd = malloc(sizeof(strcut records));
passwd->lines = malloc(sizeof(char *) * MAX_STR_SIZE);

With a few malloc error checking ( passwd is not null, passwd->lines is not null) it's passed down to my parse_file() : 通过一些malloc错误检查( passwd不为null, passwd->lines不为null),将其传递给我的parse_file()

parse_file(struct records *record, FILE * in)
{
    int i = 0;

    ... // a while loop
    fgets((*record).lines[i], MAX_STR_SIZE, in); // <-- Segment fault here
    i++;
    ... // end while
}

The file is /etc/passwd and I want to read in the first line of this file and store that into the struct records lines[i] position. 该文件为/ etc / passwd,我想读取该文件的第一行,并将其存储到struct records行[i]的位置。

I also tried this: 我也试过这个:

fgets(record->lines[i], ...) //which also gets a seg fault.

in GDB, under parse_file() scope: 在GDB中parse_file()范围内:

(gdb) p record
$1 = {struct records *} 0x602250

How can I fix this error? 如何解决此错误?

You're missing an allocation step; 您缺少分配步骤; for each passwd->lines[i] , you need to do another allocation: 对于每个passwd->lines[i] ,您需要进行另一次分配:

// Allocate space for array of pointers
passwd->lines = malloc( sizeof *passwd->lines * max_number_of_strings );
for ( size_t i = 0; i < max_number_of_strings; i++ )
{
  // Allocate space for each string
  passwd->lines[i] = malloc( sizeof *passwd->lines[i] * max_string_length );
}

You need to allocate memory for each line before you can copy data to it: 您需要为每行分配内存,然后才能将数据复制到其中:

  record->line[i] = malloc(MAX_STR_SIZE+1);    // allocate memory first.
  fgets((*record).lines[i], MAX_STR_SIZE, in); // <-- Segment fault here

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