TypeError：'str'对象不可调用（Python 2）

Question

program to check if word starts & ends with same letter

def match_letter():
    count = 0
    for word in words:
        if len(word) >=2 and word[0] == word[-1]:
            count = count + 1
    return count

def main():
    words = []
    words_list = raw_input('Enter Words: ')
    words_list = words_list().split()
    for word in words_list:
        words.append(word)

    count = match_letter()
    print 'letter matched %d ' %count

if __name__ == '__main__':
    main()

this is my python code, giving an error

Traceback (most recent call last):
  File "D:\Programming\Python\Python 2.7\same_letter.py", line 21, in <module>
    main()
  File "D:\Programming\Python\Python 2.7\same_letter.py", line 13, in main
    words_list = words_list().split()
TypeError: 'str' object is not callable

i am very thankful if anyone can help me..

Answer 1

This line has an extra parentheses

words_list = words_list().split()

It could just be

words_list = words_list.split()

In fact, you have a number of extraneous steps, your code block

words = []
words_list = raw_input('Enter Words: ')
words_list = words_list().split()
for word in words_list:
    words.append(word)

Could be reduced to:

words = raw_input('Enter Words: ').split()

And if I understand your question, I would solve this using slicing

def same_back_and_front(s):
    return s[0] == s[-1]   # first letter equals last letter

>>> words = ['hello', 'test', 'yay', 'nope']
>>> [word for word in words if same_back_and_front(word)]
['test', 'yay']

Answer 2

Thanx Cyber.. It works for me. this code works for me exactly as i want

def match_letter(words):
    count = 0
    for word in words:
        if len(word) >=2 and word[0] == word[-1]:
            count = count + 1
    return count

def main():
    words = raw_input('Enter Words: ').split()
    count = match_letter(words)
    print 'letter matched %d ' %count

if __name__ == '__main__':
    main()