在bash中的sed中循环遍历数组

Question

I have a long list (~100 lines) containing lines of names of animals, where they were spotted and when named spottings . The first 3 lines could be this:

cat 1999 madagascar 
dog 1827 peru 
kangaroo 1995 new zealand
cat 1827 england

Now I want to match that list with another list want that goes like this:

cat
dog
kangaroo

However, I only want to get the lines that also match a given year but not a given location . For examples, with 1827 and england I've done it like this:

cat spottings | grep -i -f want | sed '/1827/I!d;/england/Id'

Now, if my year and location are located in a string like this:

want="1827,1999,2013" # year
nonotwant="england,madagascar,peru" # location

which is made into an array like this:

want=($(echo ${want} | tr ',' '\n'))

If I would check for all elements of want and donotwant it would be like this:

sed spottings | grep -i -f want | sed '/1827/I!d;/1999/I!d;/2013/I!d;/england/Id;/madagascar/Id;/peru/Id'

How would I check for all elements in both arrays?

Answer 1

why not a

fgrep -i -f want spottings | fgrep -i -f WantYear | fgrep -v -f NotWantLocation

where want , WantYear and NotWantLocation are file with 1 criteria per line.