用于在保留空格的情况下拆分字符串的正则表达式

Question

I am doing an Android project which needs to split a String into tokens while preserving whitespaces and also not to split at non-word characters like # , & etc ...

Using \\b splits at any non-word character .So i need a way to split the string in the following way.

Input: ( . indicates whitespace)

A.A#..A## 

Desired output:

A
.
A#
..
A##

So these 5 lines are the 5 values I would like in an array or similar. That means the 4th element of the result-array contains 2 spaces.

Answer 1

I think this is what you want:

(?<=\S)(?=\s)|(?<=\s)(?=\S)

Debuggex Demo

Basically I'm saying "if the previous character is a non-space and the next is a space or if the previous is a space and the next is a non-space, then split".

Answer 2

Use StringTokenizer:

StringTokenizer st = new StringTokenizer("A.A#..A##", ".");//first argument is string you want to split, another is whitespace

while(st.hasMoreTokens())
  System.out.println(st.nextToken());

output will be: AA# A##

Answer 3

Try:

String s = "AA#..A##"; if(s.contains("..")) | s.contains("...")) { s.replace("..", "."); s.replace("...", "."); String out[] = s.split(".");

It should give you an array with Strings the way you want :)

Don't forget to replace the "." with actual spaces :)