MySQL：使用同一表格从上一个查询的结果中删除

Question

I get an error while trying to execute this query since MySQL realize that I'm trying to delete some records by a set of results which comes from a JOIN on the same table.

How can I rewrite the query?

DELETE FROM hr_descr2 
WHERE
    id IN (SELECT 
        a.id
    FROM
        hr_descr2 a,
        hyperreview_descr b    
    WHERE
        a.titolo = b.titolo
        AND a.recensione != b.recensione
        AND a.recensione != ''
        AND b.recensione != ''
        AND ABS(LENGTH(a.recensione) - LENGTH(b.recensione)) > 40);

I've also tried to rewrite the query in this way but it doesn't work:

WITH temp AS(SELECT 
        a.id
    FROM
        hr_descr2 a,
        hyperreview_descr b    
    WHERE
        a.titolo = b.titolo
        AND a.recensione != b.recensione
        AND a.recensione != ''
        AND b.recensione != ''
        AND ABS(LENGTH(a.recensione) - LENGTH(b.recensione)) > 40)
DELETE FROM hr_descr2 
WHERE
    id IN (select id from temp);

Answer 1

First, I don't think MySQL Supports CTEs, so the with is not syntactically correct.

I haven't tried this but I think something like this should work?

DELETE hr_descr2 
FROM hr_descr2 a,
    hyperreview_descr b    
WHERE
    a.titolo = b.titolo
    AND a.recensione != b.recensione
    AND a.recensione != ''
    AND b.recensione != ''
    AND ABS(LENGTH(a.recensione) - LENGTH(b.recensione)) > 40);

Answer 2

instead you can use

DELETE a FROM
    hr_descr2 a,
    hyperreview_descr b    
WHERE
    a.titolo = b.titolo
    AND a.recensione != b.recensione
    AND a.recensione != ''
    AND b.recensione != ''
    AND ABS(LENGTH(a.recensione) - LENGTH(b.recensione)) > 40