preg_match第一个SELECT和最后一个FROM之间的所有内容

Question

I want to have a regular expression that matches everything between the first SELECT and the last FROM in a SQL statement with PHP. To put this into an example:

SELECT
    `t1`.`id`,
    `t1`.`created`,
    (
        SELECT
            `t2`.`content`
        FROM
            `table2` `t2`
        WHERE
            `t1`.`id` = `t2`.`id`
    ) `sub`
FROM
    `table1` `t1`

In the statement above statement I want to match:

`t1`.`id`,
    `t1`.`created`,
    (
        SELECT
            `t2`.`content`
        FROM
            `table2` `t2`
        WHERE
            `t1`.`id` = `t2`.`id`
    ) `sub`

I tried doing this myself, but I can't get it working properly.

Answer 1

You can use a basic regular expression to achieve this ...

preg_match('~SELECT(.*)FROM~si', $text, $match);
echo $match[1];

Code Demo

Answer 2

(?<=SELECT\s)(.*)(?=\sFROM)

Try this.Grab the capture.See demo.

http://regex101.com/r/rQ6mK9/15

Answer 3

Use DOTALL modifier to make dot to match even newline characters also. \\K in the below regex would discard the previously matched characters from printing.

(?s)SELECT[^\n]*\n\K.*(?=[^\n]*FROM)

OR

(?s)SELECT[^\n]*\n\K.*(?=\n[^\n]*?FROM)

DEMO