Android：ListView，最小滚动位置

Question

I have 10 items in ListView. Sometimes I dont want user to be able to see first list item. So Second one should be like first one.

How to prevent user to scroll to the first item ? Or maybe there is better solutions or ready API to do that ?

PS: HeaderView not works for me

Answer 1

The best solution would be to simply remove (temporarily) the item from your List (or whichever collection you are using), and then re-fill the ListView with:

listView.notifyDataSetChanged();

Another thing you could do is return an empty view when your 'position == 0' so the first item would not be displayed you'd also have to call the 'notifyDataSetChanged()' method here when the condition would change.

Answer 2

This code will block the first item from being seen by selecting the second item on the list.

    listView.setOnScrollListener(new AbsListView.OnScrollListener() {
        @Override
        public void onScrollStateChanged(AbsListView absListView, int i) {

        }

        @Override
        public void onScroll(AbsListView absListView, int i, int i2, int i3) {
            if (i == 0)
                absListView.setSelection(1);
        }
    });