Python 2.7将字母转换为电话号码

Question

I am trying to complete a code that converts letters into a phone number sequence. What I need is to make for example JeromeB to 537-6632. Also I need the program to cut off the letter translation after the last possible digit. So for example after 1-800-JeromeB even if I write in 1-800-JeromeBrigham it will not code that. The thing is though I do not understand how to implicate that into my code. I do not know understand to cut off the last letter and put in the dash. What I currently have is this

alph = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p',\
        'q','r','s','t','u','v','w','x','y','z']
num =[2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,9,9,9,9]


phone = raw_input('enter phone number ').lower()

s = ""
for index in range(len(phone)):
    if phone[index].isalpha():
        s = s + str(num[alph.index(phone[index])])
    else:
        s = s + phone[index]
print s  

Answer 1

# define a dictionary
alph_num_dict = {'a': '2', 'b': '2', 'c': '2',\
                 'd': '3', 'e': '3', 'f': '3',\
                 'g': '4', 'h': '4', 'i': '4',\
                 'j': '5', 'k': '5', 'l': '5',\
                 'm': '6', 'n': '6', 'o': '6',\
                 'p': '7', 'q': '7', 'r': '7', 's': '7',\
                 'u': '8', 'w': '9', 'v': '8',\
                 'w': '9', 'x': '9', 'y': '9', 'z': '9'}

updated : Cut off chars which follow 7th char, and insert dash in the 4th place

# define a generator for converting string and cutting off it
def alph_to_num(phone):
    for index in range(len(phone)):
        if index >= 7:
            return

        if index == 4:
            yield '-'

        p = phone[index]

        if p in alph_num_dict:
            yield alph_num_dict[p]
        else:
            yield p

updated : Enter "end" for termination

# get input and join all converted char from generator
while True:
    phone = raw_input('enter phone number in the format xxxxxxx, or enter "end" for termination ').lower()

    if phone == 'end':
        break

    print ''.join(list(alph_to_num(phone)))

input : JeromeBrigham

output : 5376-632

Answer 2

You should use a fixed range(7) instead of range(len(phone)) if you want to always output 7 characters (and raise an error otherwise).

As for the dashes, just check the current index. If it's 3, add a dash.

Answer 3

Try using a dictionary with alphas as keys and the corresponding numbers as values, then just iterate the first 10 indexes

phone = {'A' : 2, 'B' : 2, 'C' : 2, 'D' : 3, ....}

number = input("Enter a phone number")
counter = 1
for index in number:
  if counter < 10:
    print phone[number]
  counter += 1

You can also get a substring of the input

number[:10]

Answer 4

just use fixed length, and this is so not Pythonic, below is a more elegant rewrite

# please complete this map
phone_map = {'a':'2','b':'2','c':'2','d':'3','e':'3','f':'3'} 
"".join([ phone_map[digit] if digit.isalpha() else digit for digit in "abc123abc"])

Answer 5

There is a string.maketrans function that generates a 1:1 translation mapping, and calling translate on a string and passing this mapping will translate a string in one step. Example:

import string
import re

# This builds the 1:1 mapping.  The two strings must be the same length.
convert = string.maketrans(string.ascii_lowercase,'22233344455566677778889999')

# Ask for and validate a phone number that may contain numbers or letters.
# Allows for more than four final digits.
while True:
    phone = raw_input('Enter phone number in the format xxx-xxx-xxxx: ').lower()
    if re.match(r'(?i)[a-z0-9]{3}-[a-z0-9]{3}-[a-z0-9]{4,}',phone):
        break
    print 'invalid format, try again.'

# Perform the translation according to the conversion mapping.
phone = phone.translate(convert)

# print the translated string, but truncate.
print phone[:12]

Output:

Enter phone number in the format xxx-xxx-xxxx: 123-abc-defgHIJK
123-222-3334