[英]php soap call with class
I have a webservice written in Java, and I want to use it by php. 我有一个用Java编写的Web服务,我想通过php使用它。 It need a class, say "UserDemand", as one of the parameters.
它需要一个类,例如“ UserDemand”,作为参数之一。 It works before( the code is written by others ), but I add an attribute, and it does not work anymore.
它以前可以工作(代码是由其他人编写的),但是我添加了一个属性,因此不再起作用。 The wsdl is like this:
wsdl是这样的:
<wsdl:types>
<schema xmlns="http://www.w3.org/2001/XMLSchema" targetNamespace="http://statistic.bupt.com">
<import namespace="http://bupt.com"/>
<import namespace="http://schemas.xmlsoap.org/soap/encoding/"/>
<complexType name="UserDemand">
<sequence>
<element name="callSupport" type="xsd:int"/>
<element name="caps" type="xsd:int"/>
<element name="strategy" type="xsd:int"/>
<element name="video" type="xsd:int"/>
</sequence>
</complexType>
...
The callSupport is added. 已添加callSupport。 I test the webservice with java code, it works ok.
我用Java代码测试了Web服务,它工作正常。
But when I use it with php (and use CodeIgniter), the java side can't set callSupport, it even never call the function "setCallSupport", but the strategy and other attribute can still work. 但是,当我将它与php一起使用(并使用CodeIgniter)时,Java端无法设置callSupport,它甚至永远也不会调用函数“ setCallSupport”,但是策略和其他属性仍然可以工作。 The php is ad below:
的PHP是下面的广告:
$this->load->library('UserDemand');
$userDemand = new UserDemand();
$userDemand->callSupport = $call_support;
$userDemand->caps = $audio_count;
$userDemand->video = $media_count;
$userDemand->strategy = $strategy;
$client = new SoapClient($ws_base_url.$wsdl_class.'?wsdl');
$param = array($username, $userDemand);
$out = $client->__soapCall($wsdl_function, $param);
And I just add callSupport. 我只是添加callSupport。 So, why I can't receive it, or actually it is recieved but just can't be set?
那么,为什么我不能收到它,或者实际上收到了它却无法设置?
I have find a way to solve the problem. 我找到了解决问题的方法。 Just use SoapVar to solve it.
只需使用SoapVar即可解决。
$x = new SoapVar($userDemand,SOAP_ENC_OBJECT);
$param = array($username, $x);
But I'm still confuesd about that if I have to do so, it must have been done before. 但是我仍然对此感到困惑,如果我必须这样做,那一定是以前做过的。 It means the old code should not work, but it did work!
这意味着旧代码不起作用,但确实起作用了!
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