除一个子文件夹外，所有子文件夹中都需要文件

Question

I wrote the below condition to get all *.js files from a folder and its subfolder. I wrote the below command to get the list:

c:/svn/myfolder/**/*.js

"myfolder" has 4 sub folders a, b, c, d in it and i want to get list of .js files only from three of the subfolders and skip checking the subfolder 'c' .

Currently it returns all .js files as i put myfolder/**/*.js

Answer 1

Ruby's glob syntax borrows from regex. You can specify a range of characters using brackets.

Dir['c:/svn/myfolder/[abd]/*.js']

This will include a, b, and d but not c. You can also negate:

Dir['c:/svn/myfolder/[^c]/*.js']

This will include all but c

See http://ruby-doc.org/core-2.1.3/Dir.html#method-c-glob for more info on Ruby globs.

Answer 2

You can use Dir glob to get all the files and directories as a list. To accomplish this with regex do:

Dir.glob(File.join(['c:/svn/myfolder', '*[^excluded_folder]', '**', '*.js']))

The *[^excluded_folder] includes everything but excluded_folder .

Keeping the ** as part of your path will grab files from the current directory path it's placed at as well as all subdirectories.