[英]awk + print the field from line that defined with double quotes
how to print the third field from line that defined with double quotes 如何从用双引号定义的行中打印第三个字段
for example 例如
echo activate.bash /home/adm/run.sh "run on machine with eth2 active" "94061" | awk '{print $3}'
I expected that the awk will print the third filed in the double quotes 我希望awk将打印双引号中的第三个文件
run on machine with eth2 active
but its print 但它的印刷品
run
so what's I need to fix in my ksh syntax? 所以我需要在ksh语法中解决什么?
other example 其他例子
echo 123 123 "1 2 3 4 5" | awk '{print $3}'
should print 应该打印
1 2 3 4 5
You can use custom field separator in awk like this: 您可以在awk中使用自定义字段分隔符,如下所示:
s='activate.bash /home/adm/run.sh "run on machine with eth2 active" "94061"'
echo "$s" | awk -F '"' '{print $2}'
run on machine with eth2 active
PS: Better to use: PS:更好地使用:
awk -F '"' '{print $2}' <<< "$s"
Let's take the following example: 让我们来看下面的例子:
cat numbers
123 123 "run on machine with eth2 active" "94061"
cat numbers | awk -F '"' 'BEGIN{OFS=" ";} {print $2;}'
OUTPUT: run on machine with eth2 active 输出:在启用了eth2的计算机上运行
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