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python - 列出函数的所有内部函数?

[英]python - list all inner functions of a function?

In python you can do fname.__code__.co_names to retrieve a list of functions and global things that a function references.在 python 中,您可以执行fname.__code__.co_names来检索函数列表和函数引用的全局事物。 If I do fname.__code__.co_varnames , this includes inner functions, I believe.如果我做fname.__code__.co_varnames ,我相信这包括内部函数。

Is there a way to essentially do inner.__code__.co_names ?有没有办法基本上做inner.__code__.co_names by starting with a string that looks like 'inner' , as is returned by co_varnames ?从一个看起来像'inner'的字符串开始,正如co_varnames返回的那样?

In Python 3.4+ you can get the names using dis.get_instructions .在 Python 3.4+ 中,您可以使用dis.get_instructions获取名称。 To support nested functions as well you need to recursively loop over each code object you encounter:要同时支持嵌套函数,您需要递归循环您遇到的每个代码对象:

import dis
import types

def get_names(f):
    ins = dis.get_instructions(f)
    for x in ins:
        try:
            if x.opcode == 100 and '<locals>' in next(ins).argval\
                                              and next(ins).opcode == 132:
                yield next(ins).argrepr
                yield from get_names(x.argval)
        except Exception:
            pass

Demo:演示:

def func():
    x = 1
    y = 2
    print ('foo')
    class A:
        def method(self):
            pass
    def f1():
        z = 3
        print ('bar')
        def f2():
            a = 4
            def f3():
                b = [1, 2, 3]
    def f4():
        pass

print(list(get_names(func)))

Outputs:输出:

['f1', 'f2', 'f3', 'f4']

I don't think you can inspect the code object because inner functions are lazy, and their code-objects are only created just in time.我认为您不能检查代码对象,因为内部函数是惰性的,并且它们的代码对象只是及时创建的。 What you probably want to look at instead is the ast module.您可能想要查看的是 ast 模块。 Here's a quick example:这是一个简单的例子:

import ast, inspect

# this is the test scenario
def function1():
    f1_var1 = 42
    def function2():
        f2_var1 = 42
        f2_var2 = 42
        def function3():
            f3_var1 = 42

# derive source code for top-level function
src = inspect.getsource(function1)

# derive abstract syntax tree rooted at top-level function
node = ast.parse(src)

# next, ast's walk method takes all the difficulty out of tree-traversal for us
for x in ast.walk(node):
    # functions have names whereas variables have ids,
    # nested-classes may all use different terminology
    # you'll have to look at the various node-types to
    # get this part exactly right
    name_or_id = getattr(x,'name', getattr(x,'id',None))
    if name_or_id:
        print name_or_id

The results are: function1, function2, f1_var1, function3, f2_var1, f2_var2, f3_var1.结果为:function1、function2、f1_var1、function3、f2_var1、f2_var2、f3_var1。 Obligatory disclaimer: there's probably not a good reason for doing this type of thing.. but have fun :)强制性免责声明:做这种事情可能没有充分的理由......但玩得开心:)

Oh and if you only want the names of the inner functions?哦,如果你只想要内部函数的名称?

print dict([[x.name,x] for x in ast.walk(ast.parse(inspect.getsource(some_function))) if type(x).__name__=='FunctionDef'])

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