在MySQL和关系表中加入JOIN错误

Question

I have three tables, "food","member" and "member_food". I'm trying to make an update user page where a collection of tags are prepopulated by the data in "member_food".

I have debugged the ID sending from the previous page which allows me to select the entry I wish to query, ID:4 .

$query = "SELECT * FROM `food` left join `member_food` on food.entityid = member_food.food_id WHERE member_id = '$id'";
            //Breakfast
            $breakfastresult1 = $mysqli->query($query);

echo '<select name="breakfast1">';
        while($BreakfastData1 = mysqli_fetch_array($breakfastresult1, MYSQL_ASSOC))
        {
            echo '<p><option value="' . htmlspecialchars($BreakfastData1['member_food.food_id']) . '">' 
                . htmlspecialchars($BreakfastData1['member_food.food_name']) 
                . '</option>'
                . '</p>';        
        }
echo '</select>';

However, the select fields appear to be empty. I think it's not pulling the correct values from my leftjoin table.

Here is an example of my member_food table:

food table:

Answer 1

编辑此内容，首先需要输入错误（左+联接中缺少空格），其次您需要知道哪个表member_id属于

     $query = "SELECT * FROM `food` as f left join `member_food` as mf on f.entityid = mf.food_id WHERE mf.member_id = '$id'";

Answer 2

You can use this to plan your joins correctly. And, as Abdul pointed out, typos are bad ;)