从SQL查询结果中获取计数

Question

I have such query

SELECT `id`
FROM (`TABLE`)
WHERE date(FROM_UNIXTIME(time)) >= '2013-10-28'
GROUP BY `last`
ORDER BY `id_s` DESC

the result is:

| id |

9
1
1
9
50
3
1

My question is how to count how many times repeating number 9 in result?

So, the final result must be one row with number 2

Somebody have idea how possible to do it?

Answer 1

You would use count(*) :

SELECT count(distinct last)
FROM (TABLE)
WHERE date(FROM_UNIXTIME(time)) >= '2013-10-28' AND
      id = 9 ;

I'm not sure what the group by really does, so it might be sufficient to do:

SELECT count(*)
FROM (TABLE)
WHERE date(FROM_UNIXTIME(time)) >= '2013-10-28' AND
      id = 9 ;

Answer 2

You could just use the result set that you already have, select id=9 from it and count the rows:

SELECT COUNT(*)
FROM (
  --your current query here
) WHERE `id`=9
GROUP BY `id`

There might be a better way of doing this in your situation, but without knowing your table structure and maybe seeing some example data, this is hard to tell.