创建一个dict，其值是给定单词所有可能的字谜的集合

Question

So what im trying to do is create a dict whose:

• key is the word in sorted order and
• value is the set of each anagram (generated by an anagram program).

When i run my program i get Ex. word : {('w', 'o', 'r', 'd')} not word : dorw, wrdo, rowd. Text file just contains a lot of words one on each line.

Code:

def main():
    wordList = readMatrix()
    print(lengthWord())

def readMatrix():
    wordList = []
    strFile = open("words.txt", "r")
    lines = strFile.readlines()
    for line in lines:
        word = sorted(line.rstrip().lower())
        wordList.append(tuple(word))
    return tuple(wordList)

def lengthWord():
    lenWord = 4
    sortDict = {}
    wordList = readMatrix()
    for word in wordList:
        if len(word) == lenWord:
            sortWord = ''.join(sorted(word))
            if sortWord not in sortDict:
                sortDict[sortWord] = set()
            sortDict[sortWord].add(word)
    return sortDict


main()

Answer 1

You are creating tuples of each word in the file:

for line in lines:
    word = sorted(line.rstrip().lower())
    wordList.append(tuple(word))

This will sort all your anagrams, creating duplicate sorted character tuples.

If you wanted to track all possible words, you should not produce tuples here. Just read the words:

for line in lines:
    word = line.rstrip().lower()
    wordList.append(word)

and process those words with your lengthWord() function; this function does need to take the wordList value as an argument:

def lengthWord(wordList):
    # ...

and you need to pass that in from main() :

def main():
    wordList = readMatrix()
    print(lengthWord(wordList))