泽西岛-JSON仅封送特定字段

Question

My REST service returns following JSON

{
  "name": "John",
  "id" : 10
}

Can I use Jersey to marshall it into following Bean:

public class User{
    private String name;
    //getter & setter
}

I wanted to do this with following code but it doesn't work

WebResource webResource = client.resource(url);
webResource.accept(MediaType.APPLICATION_JSON_TYPE);
User user = webResource.get(User.class);

Is this even possible or I have to implement full JSON structure in Java Beans to get it work?

I know that I can parse this JSON with Jackson and any other methods.

Answer 1

With Jackson, easiest way is to configure ObjectMapper like so:

 objectMapper.configure(DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES, 
false);

Check this sample provider

package com.company.rest.jersey;
@Provider
@Component
@Produces({MediaType.APPLICATION_JSON})
public class JacksonMapperProvider implements ContextResolver<ObjectMapper> {
   ObjectMapper mapper;

   public JacksonMapperProvider(){
       mapper = new ObjectMapper();
       mapper.configure(Feature.INDENT_OUTPUT, true);

       // Serialize dates using ISO8601 format
       // Jackson uses timestamps by default, so use StdDateFormat to get ISO8601
       mapper.getSerializationConfig().setDateFormat(new StdDateFormat());

       // Deserialize dates using ISO8601 format
       // MilliDateFormat simply adds milliseconds to string if missing so it will parse
       mapper.getDeserializationConfig().setDateFormat(new MilliDateFormat());

       // Prevent exceptions from being thrown for unknown properties
       mapper.configure(
              DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES,false);
   }

   @Override
   public ObjectMapper getContext(Class<?> aClass) {
       return mapper;
   }
}

Answer 2

With Jackson : You have two options:

1. Jackson works on setters-getters of fields. So, you can just remove getter of field which you want to omit in JSON. ( If you don't need getter at other place.)

2. Or, you can use the @JsonIgnore annotation of Jackson on getter method of that field and you see there in no such key-value pair in resulted JSON.

    @JsonIgnore public int getSecurityCode(){ return securityCode; } 

Answer 3

In your bean, add the annotation @JsonIgnoreProperties(ignoreUnknown = true) at the class level and it should skip the id property in the JSON since it's not present in the bean.

@JsonIgnoreProperties(ignoreUnknown = true)
public class User{
    private String name;
    //getter & setter
}

(See http://wiki.fasterxml.com/JacksonAnnotations for details)